Solve for y.2x - 3y = 52x - 2x - 3y = -2x + 5-3y = -2x + 5-3y/-3 = -2x/-3 + 5/-3y = (2/3)x - 3/5Clearly you see that the slope is 2/3.
2x + 3y = 6 can be written in the standard slope-intercept form of y= mx + c, where 'm' is the slope. 3y = -2x + 6 y = -⅔x + 2 The slope of this linear graph is -⅔.
2x-3y=16 Write this in standard form (y = mx+c), 3y = 2x-16 or y = 2/3x - 16/3 so the slope is 2/3
6x+3y = -9 3y = -6x-9 y = -2x-3 Therefore the perpendicular slope is 1/2
x=12 y=4
Y=4-(2x/3)
Solve for y.2x - 3y = 52x - 2x - 3y = -2x + 5-3y = -2x + 5-3y/-3 = -2x/-3 + 5/-3y = (2/3)x - 3/5Clearly you see that the slope is 2/3.
2x - 3y = 6 2x = 6 + 3y 2x - 6 = 3y : 3y = 2x - 6 y = 2/3x - 2
2x + 3y = 6 can be written in the standard slope-intercept form of y= mx + c, where 'm' is the slope. 3y = -2x + 6 y = -⅔x + 2 The slope of this linear graph is -⅔.
2x - 3y = 62x = 3y + 63y = 2x - 6y = (2x - 6)/3y = (2/3)x - 2
2x-3y = 4 -3y = -2x+4 y = 2/3x-4/3 So the slope is 2/3 and the intercept is -4/3
2X + 3Y = 24 subtract 2X from both sides 3Y = - 2X + 24 divide both sides by 3 Y = - 2/3X + 8 slope(m) = - 2/3
2x-3y=16 Write this in standard form (y = mx+c), 3y = 2x-16 or y = 2/3x - 16/3 so the slope is 2/3
It is: y = -2/3x+4 in slope intercept form
2x + 3y = 5 So 3y = -2x + 5 or y = -2/3x + 5 Now that the equation is in standard form, you just read the slope off as the coefficient of x, ie slope = -2/3
Convert the equation into the form y = mx + c, where m is the slope (and c is the y intercept) 2x + 3y = 18 3y = -2x + 18 y = -2/3x + 6 Therefore the slope is -2/3.
2/3