0
Assuming that you mean that those are the (x,y) points, then solve this by using the formula for calculating slope.
Chance in y / chance in x = slope
so,
(-5 - 0) / 0 - 0
Already you can see the problem. The denominator will equal 0, which means that it does not exist.
The slope of that line does not exist, nor does the slope for any vertical line.
On a completely separate note though, the slope of a horizontal line is 0.
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What is the slope of the line passing through points a 5 4 and b 0 3?
Slope = (change_in_y) / (change_in_x) = (4 - 3) / (5 - 0) = 1/5 = 0.2
What is the slope when m equals 0 and b equals 5?
The slope is normally represented by m so it is 0.
What is the slope of the line passing through points 5-4 and 0-3?
(5, -4) and (0, -3)Slope = ( y2-y1 ) / ( x2-x1 )= (-3 + 4) / (0 - 5) = (1) / (-5)= -0.2
What is a slope of 0?
A horizontal line has a slope of 0. If you're using the slope formula, then when the numerator is equal to 0 then the slope is 0.
What is the slope of the line passing through the points 2 5 and 0 4?
It is: (5-4)/(2-0) = 1/2
