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What is the slope of 0 0 and 0 -5?
Assuming that you mean that those are the (x,y) points, then solve this by using the formula for calculating slope. Chance in y / chance in x = slope so, (-5 - 0) / 0 - 0 Already you can see the problem. The denominator will equal 0, which means that it does not exist. The slope of that line does not exist, nor does the slope for any vertical line. On a completely separate note though, the slope of a horizontal line is 0.
What is the slope of the line that passes through these points 3-0 8-0?
The slope is zero.
What is the slope of 9 over 0?
The answer is 0.
What is the slope for y 12x?
y=12x+0 the slope is 12
What is the slope when m equals 0 and b equals 5?
The slope is normally represented by m so it is 0.
If the slope of a given line is 0 what is the slope of an orthogonal line?
If the original slope is 0, then the opposite reciprocal of 0 is still 0. Oops! Reciprocal of 0 (n/0) is undefined! A vertical line has undefined slope, the horizontal line has slope of 0.
What is slope of 0?
if you define y = constant then the slope of any constant is 0 so if you define the line y = 0 the slope of 0 is 0.
What is the slope of a line with the points 0 0 and 0 -3?
The slope is undefined.
What is the difference between slope of 0 and no slope?
No slope is undefined i.e. a vertical line slope of 0 is a horizontal line... i believe...
What is the coefficient of x in the equation of a graph that has slope 0?
y=mx has a slope of m, if the slope is 0, m must be 0. So the coefficient of x is 0.
What is the slope of these points -1 -1 and 0 0?
Points: (-1, -1) and (0, 0) Slope: 1
What is the slope of a line passing through 4 0 0 8?
Slope = (8 - 0)/(0 - 4) = -2
If the slope of a line is 0 is the line horizontal or vertical?
if the slope is 0, the line is horizontal.
What are the slope and y-intercept of a horizantal line?
Slope=0 Y-intercept=0
What is the slope of 0 0 and 0 -5?
Assuming that you mean that those are the (x,y) points, then solve this by using the formula for calculating slope. Chance in y / chance in x = slope so, (-5 - 0) / 0 - 0 Already you can see the problem. The denominator will equal 0, which means that it does not exist. The slope of that line does not exist, nor does the slope for any vertical line. On a completely separate note though, the slope of a horizontal line is 0.
Why A is zero but V is not zero?
Because V in is the slope and when A is 0 slope is not 0 so v cant be 0
What is the slope of the line through the points (0 0) and (2 6)?
Points: (0, 0) and (2, 6) Slope: 3
