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-3,5 and 6,-1

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Anonymous

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Q: What is the slope of the line containing ( 3 5) and (6 1)?
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Related questions

What is the slope of a line containing the points 1 -3 and -2 -3?

Zero


What is the slope of the line containing 2 and 3 and -6 and -4?

(3--4)/2--6) = 7/8 which is the slope of the line.


What is the slope of the line containing the given pair of points 1 2 and 9 12?

Slope = (change in Y) / (change in X) = (12 - 9) / (2 - 1) = 3 / 1 = 3


The slope of a line is -3. Find the slope of a line that is perpendicular to this line. The slope of a line is -3.?

The slope of two lines are perpendicular only if their slopes multiplied together equal -1 (m1*m2 = -1). So if a line has a slope of -3 then a line perpendicular to this one has a slope of -1/-3 or 1/3.


The slope of line a is 3 what is the slope of a line perpendicular to a?

To find the slope of a perpendicular line, take the negative reciprocal of the slope of the given line. (Flip the top and bottom of the fraction and change the sign.) The slope of 3 can be written as 3/1. The slope of a line that is perpendicular is -1/3.


Find an equation of the line having the given slope and containing the given point m equals 2 over 3 and 2 and -1?

If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7


What is the slope of the line containing the points 6 and -4 and 3 and 4?

Points: (6, -4) and (3, 4) Slope: -8/3


What is the slope of the line containing the points 2 and 6 and -3 -4?

Points: (2, 6) and (-3, -4) Slope: 2


What is the slope of the line containing the points 2 and 6 and -3 and -4?

Points: (2, 6) and (-3, -4) Slope: 2


What is the slope of the line containing the points (34) and (-610)?

If you mean points of (3, 4) and (-6, 10) then the slope is -2/3


What is the slope of a line perpendicular to a line whose slope is 3?

Slope of a line = m slope of perpendicular line = -1/m


What is the slope of a line perpendicular to a line that contains the points -3 8 and -3 -6?

Generally the slope of a line perpendicular to another line is the negative reciprocal of the slope of that line, ie if the slopes are m' and m, then mm' = -1. The line containing (-3, 8) and (-3, -6) is a vertical line (no change in x whilst y changes), so the line perpendicular to it is horizontal (no change in y whilst x changes) which has a slope of 0.