(3--4)/2--6) = 7/8 which is the slope of the line.
Points: (2, 6) and (-3, -4) Slope: 2
Zero
Points: (2, 7) and (4, 4) Slope: -3/2
If you mean points of (3, 4) and (-6, 10) then the slope is -2/3
If you mean points of: (-2, -4) and (4, 5) then the slope works out as 3/2
Points: (2, 6) and (-3, -4) Slope: 2
Points: (2, 6) and (-3, -4) Slope: 2
Zero
Points: (2, 7) and (4, 4) Slope: -3/2
If you mean points of (3, 4) and (-6, 10) then the slope is -2/3
if the slope of a line is 2/3, then the slope of a parallel line would be 2/3.
If you mean points of: (-2, -4) and (4, 5) then the slope works out as 3/2
If you mean points of: (-2, -4) and (4, 5) then the slope works out as 3/2
how to find the slope of the line between the two points (-1,2) and (3, -6). can you plaese show how
Y=2x+3 (I'm 13 and I knew that
To find the slope of the line containing the points (3, 1) and (-1, 3), use the formula for slope ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Here, ( (x_1, y_1) = (3, 1) ) and ( (x_2, y_2) = (-1, 3) ). Plugging in the values, we get ( m = \frac{3 - 1}{-1 - 3} = \frac{2}{-4} = -\frac{1}{2} ). Thus, the slope of the line is (-\frac{1}{2}).
The slope, m, of a line given 2 points is: (y2 - y1) / (x2 - x1). m = (-6 - (-9)) /(3-(-4)) or 3/7. Therefore parallel line slope is 3/7.