It is 998001.
what is the difference between the largest 8-digit number and the smallest 6-digit number
Since the last digit of 5077 is 7, the last digit of the perfect square numbers must be 1 and 6. So that we have 5077 = 712 + 62.
10^2 = 6^2 + 8^2 ie 100 = 36 + 64
6
It is 998001.
100489 is the lowest perfect square number.
6.
I would just estimate, and then try out a few in the neighborhood of my estimate until I find it.My estimate is 320.3202 = 102,400 too big3152 = 99,225 too small3162 = 99,856 too small3172 = 100,489 just rightThe smallest 6-digit perfect square is 100,489.It's the square of 317.
How about 150*6 = 900 which is a perfect square because 30*30 = 900
1,0002 = 1,000,000 so 1 less is 9992 = 998,001
The smallest even 6-digit number is 100,000 .If you also want the ones digit to be twice the ten's digit, then the smallest even 6-digitthat satisfies that additional requirement is 100,021.
what is the difference between the largest 8-digit number and the smallest 6-digit number
I am pretty sure you can figure this out on your own. Raise different numbers to the square, until you get a 4-digit result. Similary, calculate the cube of different numbers, until you get a 4-digit number. If you want the SAME number to be both a perfect square and a perfect cube, then it must be a power of 6. In that case, just experiment raising different numbers to the sixth power, until you get a 4-digit number.
Since the last digit of 5077 is 7, the last digit of the perfect square numbers must be 1 and 6. So that we have 5077 = 712 + 62.
102345
Take the smallest 6-digit even number, then subtract one from it.