Well, 4 is 2X2 and 6 is 2X3 so the number needs two 2s and one 3 :2x2x3=12
24
46 can be divided by these numbers without leaving a remainder: 1 2 23 and 46.
1 can be divided into both numbers with no remainder
62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.
The smallest number that can be divided by 2, 3, and 4 without leaving a remainder is the least common multiple (LCM) of these numbers. To find the LCM, we need to identify the prime factors of each number. The prime factors of 2 are 2, 3 is 3, and 4 is 2 x 2. The LCM is the product of the highest power of each prime factor that appears in any of the numbers, so the LCM of 2, 3, and 4 is 2 x 2 x 3 = 12. Therefore, the smallest number that can be divided by 2, 3, and 4 without leaving a remainder is 12.
Six.
12
12 is the smallest whole number that gives a remainder of 4 when it is divided by 8.
24
0.6667
Any whole number can be divided by 1 without leaving a remainder.
46 can be divided by these numbers without leaving a remainder: 1 2 23 and 46.
1 can be divided into both numbers with no remainder
103
The answer is 8.
Any multiple of that number can be.
62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.