x = 0 and y = 4
y=2x-4 y=2x-5 y=1 1=2x-4 -2x = -5 x=2/5 the solution is (x,y) = (2/5,1)
x=3
x = y = 3
y equals x plus 4 when y equals 0 then x equals 2i i is the square root of negative 1
x=4 y=4
0
-4
x = 0 and y = 4
0
y=x/4
x = -3, y = 7
It is (-1, 3).
8
No. -4 does not equal -2(1).
y=2x-4 y=2x-5 y=1 1=2x-4 -2x = -5 x=2/5 the solution is (x,y) = (2/5,1)
If for x = -1 we find the same value of y in both equations, then x = -1 will be a part of the solution of the system.Let's suppose that x = -1 is the x-coordinate of the solution of the given systemx + y = 4x - y = 6.x + y = 4-1 + y = 4-1 + 1 + y = 4 + 1y = 5x - y = 6-1 - y = 6-1 - 6 + y - y = 6 - 6 + y-7 = ySince we have two different values for y, we say that x = -1 is not a part of the solution for the given system.