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You've given three figures here which makes me think that they are the sides of a three dimensional figure. But you've asked for the square centimetres. This is not possible. Square centimetres would give you the area of a flat object, but you'd need cubic centimtres for a three dimensional one.
The answer to the maths in your question is 12, but they are not square centimetres.
What else can I help you with?
How many 3cm squares and 2cm squares do you need to get a total area 35sq cm?
You would need two 3 cm squares and two 2 cm squares to get a total area of 35 sq cm. A 3 cm square has an area of 9 sq cm and a 2 cm square has an area of 4 sq cm.
What is the ares of a triangle with the height of 12 cm and a base of 4 cm?
24 cm sq
Find the area of a circle 15 ft?
Area_circle = π × radius²It depends to what the 15 ft refers, if:15 ft is the radius of the circlearea = π × (15 ft)² = 225π sq ft ≈ 707 sq ft 15 ft is the diameter of the circlediameter = radius × 2 → radius = ½ diameter→ area = π × (15 ft / 2)² = 225π/4 sq ft ≈ 177 sq ft15 ft is the circumference of the circlecircumference = 2 × π × radius → radius = circumference ÷ (2π)→ area = π × (15 ft / 2π)² = 225/(4π) sq ft ≈ 17.9 sq ft
How do you find the perimeter of a rectangular field whose length is four times its width and which has an area equal to 30976 sq cm?
Let its length be 4x and its width be x:-So: 4x times x = 30976 sq cm => 4x squared = 30976 sq cmThen: x = square root of 30976/4 => 88Perimeter: (4*88)+(4*88)+88+88 = 880 cmCheck: (4*88)*88 = 30976 sq cm
What is the volume of a candy box measured 6 cm by 4 cm and 2 cm?
(6 cm) x (4 cm) x (2 cm) = 48 cm^3 which is 48 cubic centimeters
What is the ratio of the first to the second if the areas of 2 rectangles are 15 sq cm and 60 sq cm.?
1:4
Ratio of rectangles of 15 sq cm and 60 sq cm?
1:4
The area of 2 rectangles are 15 sq cm and 60 sq cm what is the ratio of the first to the second?
The ratio is 15/60 or .25=25% So 15 is 25% of 60. This is also equal to 1/4. 15/5=3 60/5=12 15/60=3/12=1/4
Draw a shape that has a perimeter of 12 and an area of 6 sq cm?
A rectangle with dimensions 3 cm by 2 cm would meet the criteria. The perimeter is calculated as (2(length + width) = 2(3 + 2) = 10) cm, which does not satisfy the requirement. However, a rectangle with dimensions 4 cm by 1 cm has a perimeter of 10 cm and an area of 4 sq cm. A shape like a triangle with a perimeter of 12 cm and an area of 6 sq cm could be a right triangle with sides of 3 cm, 4 cm, and 5 cm.
How many square centimeters are in an area of 4.00 inches squared?
1 in = 2.54 cm (exactly) 1 sq in = 1 in x 1 in = 2.54 cm x 2.54 cm = 6.4516 sq cm ⇒ 4 sq in = 4 x 6.4516 sq cm = 25.8064 sq cm ≈ 25.81 sq cm
What are the lengths of the parallel sides of a quadrilateral which has one parallel side greater by 5 cm than the other side and has a height of 4 cm with an area of 50 square cm?
Let the lengths be x and x +5: Area = 1/2*(x+x+5)*4 = 50 sq cm Multiply both sides by 2 and multply out the brackets: 8x+20 = 100 8x = 100-20 8x = 80 x = 10 Therefore: the parallel sides are 10 cm and 15 cm Check: 1/2*(10+15)*4 = 50 sq cm
How many 3cm squares and 2cm squares do you need to get a total area 35sq cm?
You would need two 3 cm squares and two 2 cm squares to get a total area of 35 sq cm. A 3 cm square has an area of 9 sq cm and a 2 cm square has an area of 4 sq cm.
How many cm is equal to 4 by 400 meters?
first ,calculating the product =4 X 400 . =1600 sq m. Now, 1 sq m to 1 sq .cm . 1 sq m =10000 sq cm. 1600 sq. m =16000000 sq .cm.
What is the exact value of cos 15?
It is: cos(15) = (sq rt of 6+sq rt of 2)/4
What two numbers add up to 4 and multiply to -236?
-232
How many square centimeters are in 4 inches?
1 in = 2.54 cm (exactly) ⇒ 4 sq in = 4 x (1 sq in) = 4 x (1 in x 1 in) = 4 x (2.54 cm x 2.54 cm) = 4 x 6.4516 sq cm = 25.8064 sq cm ≈ 25.8 sq cm
What is the surface area of a cube with sides of 4 cm and 2?
The surface area of a cube with sides of 4 cm is 6*42 square cm = 96 sq cm. The surface area of a cube with sides of 2 units is 6*22 square units = 24 sq units.
