In any base other than 2 (ie other than binary): 10101010 + 01111 = 10102121 In base 2 (binary): 10101010 + 01111 = 10111001
170
Decimal: 170Hex: AA
2 + 8 + 32 + 128 ie 170
how to express the sum 257 and 431 in decimal form
10101010 + 01111 = 10111001 (170+15 = 185)
In any base other than 2 (ie other than binary): 10101010 + 01111 = 10102121 In base 2 (binary): 10101010 + 01111 = 10111001
10101010 in decimal = 9A2112 in Hex.
170
Decimal: 170Hex: AA
The binary number 10101010 is equivalent, in decimal representation, to 128 + 32 + 8 + 2 = 170. But this answer assumes that the given number is binary - an assumption for which there is no real justification. Besides, the relationship is an equivalence, which is not quite "the same thing".
In decimal it is 170. It is the ASCII code for the ¬ character.
2 + 8 + 32 + 128 ie 170
337
No, the sum of a repeating decimal and a terminating decimal is never a terminating decimal.
10101010 = 10^7 + 10^5 + 10^3 + 10.
101010100