10,101,010 + 01,111 = 10,102,121
Although you didn't say so, we suspect that you may have meant
the two numbers in the question to be binary (base-2) numbers.
If so, then
| 0 | 0 | 0 | 0= (170)10
0 | | | | = (15)10
Their sum is (185)10
In any base other than 2 (ie other than binary): 10101010 + 01111 = 10102121 In base 2 (binary): 10101010 + 01111 = 10111001
170
Decimal: 170Hex: AA
2 + 8 + 32 + 128 ie 170
how to express the sum 257 and 431 in decimal form
10101010 + 01111 = 10111001 (170+15 = 185)
In any base other than 2 (ie other than binary): 10101010 + 01111 = 10102121 In base 2 (binary): 10101010 + 01111 = 10111001
10101010 in decimal = 9A2112 in Hex.
170
Decimal: 170Hex: AA
The binary number 10101010 is equivalent, in decimal representation, to 128 + 32 + 8 + 2 = 170. But this answer assumes that the given number is binary - an assumption for which there is no real justification. Besides, the relationship is an equivalence, which is not quite "the same thing".
2 + 8 + 32 + 128 ie 170
337
The binary code 10101010 represents the decimal number 170. In binary code, each digit is a power of 2, starting from the right with 2^0. Therefore, the binary digit 1 in the rightmost position represents 2^0, which is 1. Adding up the values of each digit in the binary code 10101010 gives 128 + 32 + 8 + 2 = 170 in decimal form.
No, the sum of a repeating decimal and a terminating decimal is never a terminating decimal.
10101010 = 10^7 + 10^5 + 10^3 + 10.
101010100