Well, assuming that x ∈ R and assuming that by "sum" you mean the sum of the area under curve and above the line y=0, and that the term you are giving is a function where f(x) = 10x - 62, then..
f(x) = 10x - 36
∴∫f(x)dx = 5x2 - 36x + C
Now, if you know the range in which you want this area, you can say:
a
∫f(x)dx = 5a2 - 36a - 5b2 + 36b
b
But I'm guessing that this isn't a calculus question at all, and that you should probably go do your own homework.
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The operators are missing, the possible factorisations are:4x2 + 10x + 6 = 2(2x + 3)(x + 1)4x2 - 10x + 6 = 2(2x - 3)(x - 1)4x2 + 10x - 6 = 2(2x - 1)(x + 3)4x2 - 10x - 6 = 2(2x + 1)(x - 3)
-10x-6 = -12 -10x = -12+6 -10x = -6 x = 3/5
The sum of -8 and 6 is -2
2-10x = -8
6-3x = 5x-10x+10 6-3x = -5x+10 -3x+5x = 10-6 2x = 4 x = 2