Q: What is the sum of 72 and 9 is?

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9 and 8

72.

If the last 3 digits are divisible by 8 and the sum of the digits are divisible by 9.

72+81+90=243

The sum of 3/8 and 4/9 is 59/72.

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The sum is: 72+9 = 81

-54

9 and 8

72.

8 + 9 = 17 8 x 9 = 72

72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.

72 = 1*72 = 2*36 = 3*24 = 4*18 = 6*12 = 8*9

9, 18 27 36 45 54 63 72 81 90

x+x^2=72x^2 +x -72=0 (x+9)(x-8)=0 x=-9 or x=8

If the last 3 digits are divisible by 8 and the sum of the digits are divisible by 9.

72+81+90=243

The sum of 3/8 and 4/9 is 59/72.