-2(x + 9) = -8
-2x - 18 = -8
-2x = 10
x = -5
Let the number be x: 2(2x+4) = 3x+4 4x+8 = 3x+4 4x-3x = 4-8 x = -4
2 x 6 + 0 = 12 2 x 1 + 2 = 4 4 is not [divisible by] 8, so 60 is not divisible by 8. (The remainder when 60 is divided by 8 is 4). To test divisibility by 8: Add together the hundreds digit multiplied by 4, the tens digit multiplied by 2 and the units (ones) digit. If this sum is divisible by 8 so is the original number. (Otherwise the remainder of this sum divided by 8 is the remainder when the original number is divided by 8.) If you repeat this sum on the sum until a single digit remains, then if that digit is 8, the original number is divisible by 8 otherwise it gives the remainder when the original number is divided by 8 (except if the single digit is 9, in which case the remainder is 9 - 8 = 1).
A perfect number is the sum of its divisors; for example 6 is a perfect number because the sum of its divisors is 6 (1 + 2 + 3). The sum of the divisors of 8 is 7 (1 + 2 + 4), so 8 is not a perfect number.
2 x 2 x 2 = 8
A single number cannot have a sum, or a quotient.
The numbers that the sum of them is 8 and the product of them multiplied is 12 is 2 and 6 because 6 multiplied by 2 is 12, and 2+6 is always 8. Hope this helps!
8
Let the number be x: 2(2x+4) = 3x+4 4x+8 = 3x+4 4x-3x = 4-8 x = -4
If: -3*(x+8) = -21 Then: x = -1
48. 4+2=6x8=48
2 x 6 + 0 = 12 2 x 1 + 2 = 4 4 is not [divisible by] 8, so 60 is not divisible by 8. (The remainder when 60 is divided by 8 is 4). To test divisibility by 8: Add together the hundreds digit multiplied by 4, the tens digit multiplied by 2 and the units (ones) digit. If this sum is divisible by 8 so is the original number. (Otherwise the remainder of this sum divided by 8 is the remainder when the original number is divided by 8.) If you repeat this sum on the sum until a single digit remains, then if that digit is 8, the original number is divisible by 8 otherwise it gives the remainder when the original number is divided by 8 (except if the single digit is 9, in which case the remainder is 9 - 8 = 1).
(28 + 76)/13 = 104/13 = 8
A perfect number is the sum of its divisors; for example 6 is a perfect number because the sum of its divisors is 6 (1 + 2 + 3). The sum of the divisors of 8 is 7 (1 + 2 + 4), so 8 is not a perfect number.
s= -8 + n, or s=n - 8, where s is the sum and n is the number
Working backwards: 40 divided by -5 gives you -8. Set up an equation as x+2=-8 & solve for x. x=-10.Now checking: -10+2=-8-8 x -5 = 40
8n + 2
2 x 2 x 2 = 8