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What is the sum of all 4 digit numbers that can be formed using digits 0179no repetition?
To make this simpler, I'll assume that numbers with a leading zero like 0179 are "four digit numbers" for the purposes of this question.
The number of such numbers that can be formed by those numbers without repeating one of the digits is 4x3x2x1 = 24.
We could list them all and add them up, but let's instead just realize that we can choose any digit and put it in any position, and the other digits can then be arranged in 3x2x1 = 6 ways.
So the sum for any position is (0+1+7+9)*6 = 102, and the sum of the set of "four digit" numbers is 102x1000+102x100+102x10+102 = 113322.
You can figure out for yourself what the sum would be if you exclude the numbers that are really three digit numbers (hint: use the technique above to find the sum of the three digit numbers that can be formed using the digits 1, 7, and 9; then subtract that from the other total).
What else can I help you with?
How many odd numbers less than 100 can be formed by using the digits 0 3 5 7 when repetition fo digits is not allowed?
9 odd numbers less than 100 can be formed. They are: 3,5,7,35,37,53,57,73 and 75.
How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many 3-digit numbers can be formed using the digits 0 2 3 without repetition?
# 230 # 203 # 320 # 302
How many 4-digit numbers can be formed using the digits 1 2 3 4 5 6 7 8 and 9?
With repetition, 94 = 6561. Without repetition, 9*8*7*6 = 3024.
How many 6 digit numbers can be formed using the digits 123456789?
There are 60480 numbers.
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many numbers can be formed using the digits 37 and 9 without repetition?
15 of them.
How many 4 digit numbers can be formed from digits 123456789?
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many 3 digits odd numbers can be formed from the digits 1 2 3 4 and 5 if repetition is not allowed?
125
How many three digit numbers can be formed using the digits 873 and 6 without repetition?
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
How many 3-digit numbers can be formed by the digits 4 5 9 without repetition?
Six (6)
How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?
There are 2000 such numbers.
How many odd numbers less than 100 can be formed by using the digits 0 3 5 7 when repetition fo digits is not allowed?
9 odd numbers less than 100 can be formed. They are: 3,5,7,35,37,53,57,73 and 75.
How many 2-digit numbers can be formed using the digits 1 3 7 if repetition of digits is allowed?
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
What is the sum of all the four digit numbers formed using the digits 0 1 2 and 3 if repetition is allowed?
It is 415968.
