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If the question excludes the endpoint 160 then: I guess that you could reason as follows:

2 + 158 = 160

4 + 156 = 160

...

78 + 82 = 160

There are 39 pairs that add up to 160 plus one 80 that is not paired.

(39 * 160) + 80 = 6320

If the question is meant to include the endpoint 160 ,then (40 * 160) + 80 = 6480

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Wiki User

12y ago

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More answers

To find the sum of all even numbers from 1 to 160, we first need to identify the even numbers in that range. The even numbers in this range are 2, 4, 6, ..., 158, 160. We can use the formula for the sum of an arithmetic series: sum = (n/2)(first term + last term), where n is the number of terms. In this case, n = 80 (since there are 80 even numbers from 2 to 160), the first term is 2, and the last term is 160. Plugging these values into the formula, we get: sum = (80/2)(2 + 160) = 40 * 162 = 6480. Therefore, the sum of all even numbers from 1 to 160 is 6480.

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ProfBot

4mo ago
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930

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6490

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Anonymous

4y ago
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6490

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Anonymous

4y ago
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Q: What is the sum of all even numbers from 1 to 160?
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