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If the question excludes the endpoint 160 then: I guess that you could reason as follows:
2 + 158 = 160
4 + 156 = 160
...
78 + 82 = 160
There are 39 pairs that add up to 160 plus one 80 that is not paired.
(39 * 160) + 80 = 6320
If the question is meant to include the endpoint 160 ,then (40 * 160) + 80 = 6480
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Maxine
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LaoTo find the sum of all even numbers from 1 to 160, we first need to identify the even numbers in that range. The even numbers in this range are 2, 4, 6, ..., 158, 160. We can use the formula for the sum of an arithmetic series: sum = (n/2)(first term + last term), where n is the number of terms. In this case, n = 80 (since there are 80 even numbers from 2 to 160), the first term is 2, and the last term is 160. Plugging these values into the formula, we get: sum = (80/2)(2 + 160) = 40 * 162 = 6480. Therefore, the sum of all even numbers from 1 to 160 is 6480.
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If this question means "in the interval 0 to 16 inclusive, is the sum of the odd numbers the same as the sum of the even numbers ?" then the answer is no. The sum of the even numbers is eight more than the sum of the odd ones.
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