make an A.P i.e:- 2,4,6,8..................200
therefore a=2
d=2
an=200
a+(n-1)d=200
2+(n-1)(2)=200
(n-1)(2)=198
N=100
Sn=100/2+[2+200]
sn=50[202]
sn=10100
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therefore sum of first even natural numbers is 10100
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The sum of the first 100 natural numbers is 5,001.
The sum of the first 100 positive even numbers is 10,100.
The sum of the first 100 even numbers is 10,100
The sum of all the first 100 even numbers is 10,100.
50.5