The average of the four numbers will be equal to 116/4 = 29 Since you are looking for an even number of integers, you cannot have them averaging an odd number.
I assume you meant "sum". The answer is 60. 60=4 (integers) * 15 (average value of the integers). average of 4 integers = 15 --> (a + b + c + d)/4 = 15 --> (a + b + c + d) = 15 * 4 --> (a + b + c + d) = 60
The integers are 81, 83, 85 and 87.
19, 20,21,22
The answer to that question is 6,7,8,9.
The average of the four numbers will be equal to 116/4 = 29 Since you are looking for an even number of integers, you cannot have them averaging an odd number.
I assume you meant "sum". The answer is 60. 60=4 (integers) * 15 (average value of the integers). average of 4 integers = 15 --> (a + b + c + d)/4 = 15 --> (a + b + c + d) = 15 * 4 --> (a + b + c + d) = 60
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
The integers are 21, 22, 23 and 24.
The integers are 6, 7, 8 and 9.
6,7,8,9
The integers are 17, 19, 21 and 23.
The integers are 26, 27, 28 and 29.
27 + 28 + 29 + 30 = 114
The integers are -2, 0, 2 and 4.
No.
The integers are 81, 83, 85 and 87.