118
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
Let the integers be x, (x+1) and (x+2) Since, x+(x+1)+(x+2) = -114, by solving the equation for x, we get that, x = -37 Hence the integers are -37, -36 and -35
The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123
114 through 126 are all composite.
The numbers are 27, 28, 29 and 30.
118
The integers are 27, 28, 29 and 30.
27+28+29+30=114
27, 28, 29 and 30.
The consecutive odd integers for 114 are 37, 38 and 39.
27, 28, 29 and 30
27 28 29 30
117
27 + 28 + 29 + 30 = 114
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
The integers are 37, 38 and 39.