27 + 28 + 29 + 30 = 114
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118
27, 28, 29 and 30
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
The integers are 37, 38 and 39.
114/4 = 28.5 So the 4 numbers are 27, 28, 29 and 30