118
27, 28, 29 and 30
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
The integers are 37, 38 and 39.
114/4 = 28.5 So the 4 numbers are 27, 28, 29 and 30
The numbers are 27, 28, 29 and 30.
118
The integers are 27, 28, 29 and 30.
27+28+29+30=114
27, 28, 29 and 30.
The consecutive odd integers for 114 are 37, 38 and 39.
27, 28, 29 and 30
27 28 29 30
117
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
27 + 28 + 29 + 30 = 114
The integers are 37, 38 and 39.