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N+5=n+5

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13y ago

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How do you write five times the sum of 9 and a number?

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What is five times the sum of 6 and some number?

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What is the sum of five and twice a number?

Let 'n' represent any number, and 'S' represent sum. S = 5 + 2n


What is twice the sum of seven and five equals the opposite of n?

2(7+5)=n 2(12)=n 24=n but its an opposite n, so the answer is -24


What is the sum of five times a number and eight less than the number?

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What is the sum expression for the sum of n and 5?

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Write a c program to add the digits of a given no?

THIS IS ONLY FOR UPTO A FIVE DIGIT NO. BY ROHAN ARORA#include#includevoid main(){int a,n,s,sum=0;clrscr();printf("Enter the number between 1 to 5 digits\n");scanf("%d",&a);while(a!=0){n=a%10;sum=sum+n;a=a/10;}printf("The sum of digits of the given numberis %d",sum);getch();}


How do you find the Algorithm of the sum of the first five natural numbers?

To find the algorithm for the sum of the first five natural numbers, you can use the formula ( S_n = \frac{n(n + 1)}{2} ), where ( n ) is the number of terms. For the first five natural numbers, plug in ( n = 5 ): ( S_5 = \frac{5(5 + 1)}{2} = \frac{5 \times 6}{2} = 15 ). Thus, the sum of the first five natural numbers is 15. Alternatively, you could also simply add them directly: ( 1 + 2 + 3 + 4 + 5 = 15 ).


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540 degrees according to the formula: 180(n-2)


What five consecutive numbers add up to 100?

Let the five consecutive numbers be represented as n-2, n-1, n, n+1, and n+2. The sum of these numbers can be expressed as (n-2) + (n-1) + n + (n+1) + (n+2) = 5n. Setting this sum equal to 100 gives us 5n = 100. Solving for n, we find n = 20. Therefore, the five consecutive numbers that add up to 100 are 18, 19, 20, 21, and 22.


C code that will give the sum of an entered input?

#include<stdio.h> #include<conio.h> main() { int n,sum=0; printf("enter n value"); scanf("%d",n); while(n!=0) { n=n/10; sum=sum+n; n=n%10; } printf("sum is=%d",sum }