N+5=n+5
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5 x (6 + n)
Let the five consecutive numbers be represented as n-2, n-1, n, n+1, and n+2. The sum of these numbers can be expressed as (n-2) + (n-1) + n + (n+1) + (n+2) = 5n. Setting this sum equal to 100 gives us 5n = 100. Solving for n, we find n = 20. Therefore, the five consecutive numbers that add up to 100 are 18, 19, 20, 21, and 22.
The sum of n and the sum of 8 and 6 can be represented as n + (8 + 6). Simplifying the expression within the parentheses first, we get n + 14. Therefore, the final expression representing the sum of n and the sum of 8 and 6 is n + 14.
If you want to sum up numbers 1 to N, you can do it this way. Sum = (N+1)*(N/2).The reason this works: say you want to sum up 1 through 10. You have 10+1, 9+2, ..., 6+5. Each of these equals 11 [N+1]. You added 11 five times (N/2). Sum of 1 to 102 = (102+1)*(102/2) = 103*51 = 5253. You can check it by summing up the numbers with a spreadsheet.
sum = 0 for(n = 0; n <= 10; n += 2) sum += n;