N+5=n+5
5 x (6 + n)
Let the five consecutive numbers be represented as n-2, n-1, n, n+1, and n+2. The sum of these numbers can be expressed as (n-2) + (n-1) + n + (n+1) + (n+2) = 5n. Setting this sum equal to 100 gives us 5n = 100. Solving for n, we find n = 20. Therefore, the five consecutive numbers that add up to 100 are 18, 19, 20, 21, and 22.
The sum of n and the sum of 8 and 6 can be represented as n + (8 + 6). Simplifying the expression within the parentheses first, we get n + 14. Therefore, the final expression representing the sum of n and the sum of 8 and 6 is n + 14.
If you want to sum up numbers 1 to N, you can do it this way. Sum = (N+1)*(N/2).The reason this works: say you want to sum up 1 through 10. You have 10+1, 9+2, ..., 6+5. Each of these equals 11 [N+1]. You added 11 five times (N/2). Sum of 1 to 102 = (102+1)*(102/2) = 103*51 = 5253. You can check it by summing up the numbers with a spreadsheet.
sum = 0 for(n = 0; n <= 10; n += 2) sum += n;
5+9(n)
5 x (6 + n)
Let 'n' represent any number, and 'S' represent sum. S = 5 + 2n
2(7+5)=n 2(12)=n 24=n but its an opposite n, so the answer is -24
5*n + (n - 8) = 5n + n - 8 = 6n - 8
The sum of n and 5 is n+ 5
The question is ambiguous and the possible answers are n + 5*6 = n + 30 or (n + 5)*6
THIS IS ONLY FOR UPTO A FIVE DIGIT NO. BY ROHAN ARORA#include#includevoid main(){int a,n,s,sum=0;clrscr();printf("Enter the number between 1 to 5 digits\n");scanf("%d",&a);while(a!=0){n=a%10;sum=sum+n;a=a/10;}printf("The sum of digits of the given numberis %d",sum);getch();}
540 degrees according to the formula: 180(n-2)
#include<stdio.h> #include<conio.h> main() { int n,sum=0; printf("enter n value"); scanf("%d",n); while(n!=0) { n=n/10; sum=sum+n; n=n%10; } printf("sum is=%d",sum }
Let the five consecutive numbers be represented as n-2, n-1, n, n+1, and n+2. The sum of these numbers can be expressed as (n-2) + (n-1) + n + (n+1) + (n+2) = 5n. Setting this sum equal to 100 gives us 5n = 100. Solving for n, we find n = 20. Therefore, the five consecutive numbers that add up to 100 are 18, 19, 20, 21, and 22.
void main () { int no1, sum, n; clrscr() sum = 0; n = 1; printf("\n enter the number to which sum is to be generated"); scanf("%d",&no1); while(n<=no1) { sum=sum+n; n=n+1 } printf("\n the sum of %d = %d, no1, sum"); getch (); }