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How do you Factor 3r squared equals 13r plus 10?
(3r + 2)(r - 5)
Solve 4r plus 3 equals 3r- 2 for r?
4r +3 = 3r-2 r + 3=-2 r=-5 basically collect terms so that you get one coefficient of r (in this case 4r on one side and 3r on the other. To get the three r over to the other side you subtract 3r on both sides.) Then r+ 3=-2, so that's simple algebraic manipulation.
Multiply r2 plus 7r plus 10 over 3 by 3r-30 over r2-5r-50?
multiply r2+7r+10/3 by 3r-30/r2-5r-50 weegy
What is the sum of all the positive proper fractions with denominators less than or equal to 100?
Consider a denominator of r; It has proper fractions: 1/r, 2/r, ...., (r-1)/r Their sum is: (1 + 2 + ... + (r-1))/r The numerator of this sum is 1 + 2 + ... + (r-1) Which is an Arithmetic Progression (AP) with r-1 terms, and sum: sum = number_of_term(first + last)/2 = (r-1)(1 + r-1)/2 = (r-1)r/2 So the sum of the proper fractions with a denominator or r is: sum{r} = ((r-1)r/2)/r = ((r-1)r/2r = (r-1)/2 Now consider the sum of the proper fractions with a denominator r+1: sum{r+1} = (((r+1)-1)/2 = ((r-1)+1)/2 = (r-1)/2 + 1/2 = sum{r) + 1/2 So the sums of the proper fractions of the denominators forms an AP with a common difference of 1/2 The first denominator possible is r = 2 with sum (2-1)/2 = ½; The last denominator required is r = 100 with sum (100-1)/2 = 99/2 = 49½; And there are 100 - 2 + 1 = 99 terms to sum So the required sum is: sum = ½ + 1 + 1½ + ... + 49½ = 99(½ + 49½)/2 = 99 × 50/2 = 2475
Sum of individual digits of number?
void main() { int num,r,sum=0; clrscr(); printf("enter the number\n"); scanf("%d",&num); while(num!=0) { r=num%10; sum=sum+r; num=num/10 } printf("The sum of individual digit of given number is=%d",sum); getch() }
r=1+3r-3r?
1/99 − 1/100 = 1/9900
What is 3R?
If: 3r-8 = 2-2r Then: 5r = 10 And: r = 2
How do you Factor 3r squared equals 13r plus 10?
(3r + 2)(r - 5)
What is 3r-8 equals2-2r?
If: 3r-8 = 2-2r Then: 5r = 10 And: r = 2
13r plus 10 equals 5r-46?
3r+10=5r-46 --> add 46 to both sides 3r+10+46=5r-46+46 3r+56=5r --> subtract 3r from both sides 3r+56-3r=5r-3r 56=2r --> divide both sides by 2 56/2=2r/2 28=r
What is 3r-r equals 12?
3r-r equals 12 = -9
Can r plus 2r - 3r be simplified?
5
What is the answer for this math algebra problem 3r-2 for r equals 65?
3r-2 for r=65
What is r in this equation and how do you do it minus 5 equals 7 plus 3r?
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
What is the factor for 3r 12?
If that's 3r + 12, that factors to 3(r + 4)
What is triple r in algebraic expression?
Triple r in an algebraic expression simply means multiplying the variable r by 3. So if you see "3r" in an expression, it's the same as saying "triple r." It's like saying "three times the fun with r" in math language.
Which pair of values is the solution to the system of equations below r plus 2t equals -3 and 3r-4t equals -9?
r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)
