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To find the sum of the first 100 positive multiples of 4, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, a1 = 4, an = 4*100 = 400, and n = 100. Plugging these values into the formula, we get: Sn = 100/2 * (4 + 400) = 50 * 404 = 20,200. Therefore, the sum of the first 100 positive multiples of 4 is 20,200.
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What is the sum of the first 100 positive even numbers?
The sum of the first 100 positive even numbers is 10,100.
What is the sum of the first 15 multiples of 8?
Sum of the first 15 positive integers is 15*(15+1)/2 = 120 Sum of the first 15 multiples of 8 is 8*120 = 960
The sum of the first positive 100 odd numbers?
The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)
What is the sum of the first 25 multiples of 12?
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
What is the sum of the first 100 multiples of 3?
The solution to the given problem can be obtained by sum formula of arithmetic progression. In arithmetic progression difference of two consecutive terms is constant. The multiples of any whole number(in sequence) form an arithmetic progression. The first multiple of 3 is 3 and the 100th multiple is 300. 3, 6, 9, 12,... 300. There are 100 terms. The sum 3 + 6 + 9 + 12 + ... + 300 can be obtained by applying by sum formula for arithmetic progression. Sum = (N/2)(First term + Last term) where N is number of terms which in this case is 100. First term = 3; Last term = 300. Sum = (100/2)(3 + 300) = 50 x 303 = 15150.
What is the sum of the first 100 positive even numbers?
The sum of the first 100 positive even numbers is 10,100.
What is the sum of the first 15 multiples of 8?
Sum of the first 15 positive integers is 15*(15+1)/2 = 120 Sum of the first 15 multiples of 8 is 8*120 = 960
The sum of the first 100 positive even numbers?
The sum of the first 100 positive even numbers can be calculated using the formula for the sum of an arithmetic series: n*(first term + last term)/2. In this case, the first term is 2, the last term is 200, and n is 100. Therefore, the sum is 10,100.
Sum of the first 100 positive even integers?
10100.
What is the sum of the first 10 multiples of 3?
The sum of the first 10 multiples of 3 is 165.
The sum of the first positive 100 odd numbers?
The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)
What is the sum of the first 100 positive numbers?
We have to assume that you're talking about whole numbers. The sum is 5,050 .
What is the sum of numbers that are multiples of 4 less than 100?
Their sum is 1200.
What is the sum of the multiples of seven between 100 and 1000?
69342
What is the sum of the first 88 positive multiples of 3?
Sum_ap = ½ × number_of_terms × (first_term + last_term) For the first 88 multiples of three: number_of_terms = 88 first_term = 1 × 3 = 3 last_term = 88 × 3 = 264 → Sum = ½ × 88 × (3 + 264) = 44 × 267 = 11748
What are the last two digits in the sum of factorials of the first 100 positive integers?
They are 13.
What is the sum of the first 25 multiples of 12?
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
