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2013-01-21 20:28:31
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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: What is the sum of the first 100 positive multiples of 4?
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Related questions

What is the sum of the first 100 positive even numbers?

The sum of the first 100 positive even numbers is 10,100.


The sum of the first 100 positive even numbers?

The sum of the first 100 positive even numbers is 10,100.


What is the sum of the first 15 multiples of 8?

Sum of the first 15 positive integers is 15*(15+1)/2 = 120 Sum of the first 15 multiples of 8 is 8*120 = 960


Sum of the first 100 positive even integers?

10100.


What is the sum of the first 10 multiples of 3?

The sum of the first 10 multiples of 3 is 165.


The sum of the first positive 100 odd numbers?

The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)


What is the sum of the first 100 positive numbers?

We have to assume that you're talking about whole numbers. The sum is 5,050 .


What is the sum of numbers that are multiples of 4 less than 100?

Their sum is 1200.


What is the sum of the first 500 multiples of three?

The sum is 375,750.


What is the sum of the multiples of seven between 100 and 1000?

69342


What are the last two digits in the sum of factorials of the first 100 positive integers?

They are 13.


What is the sum of the first 100 multiples of 3?

The solution to the given problem can be obtained by sum formula of arithmetic progression. In arithmetic progression difference of two consecutive terms is constant. The multiples of any whole number(in sequence) form an arithmetic progression. The first multiple of 3 is 3 and the 100th multiple is 300. 3, 6, 9, 12,... 300. There are 100 terms. The sum 3 + 6 + 9 + 12 + ... + 300 can be obtained by applying by sum formula for arithmetic progression. Sum = (N/2)(First term + Last term) where N is number of terms which in this case is 100. First term = 3; Last term = 300. Sum = (100/2)(3 + 300) = 50 x 303 = 15150.

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