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The sum of the first 5 terms of an arithmetic series is 85. The sum of the first 6 terms is 123. Determine the first four terms of the series.?
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
What is the mean of 10 10 10 and 2?
(Sum of terms)/(number of terms) (10+10+10+2)/4=8
The 7th term of an arithmetic progression is 6 The sum of the first 10 terms is 30 Find the 5th term of the progression?
2
Find the sum of the first 48 terms of an aritmetic sequance 2 4 6 8?
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
Find the sum of first 10 even numbers?
The sum of the first 10 even numbers is 110.
The sum of the first 5 terms of an arithmetic series is 85. The sum of the first 6 terms is 123. Determine the first four terms of the series.?
Suppose the first term is a, the second is a+r and the nth is a+(n-1)r. Then the sum of the first five = 5a + 10r = 85 and the sum of the first six = 6a + 15r = 123 Solving these simultaneous equations, a = 3 and r = 7 So the first four terms are: 3, 10, 17 and 24
What are the first ten terms of a sequence whose first term is -10 and whose common difference is -2.?
-8
The sum of the first 20 terms of an a.p is 45 and the sum of the first 40 terms is 290. Find the first term?
-69
What is the mean of 10 10 10 and 2?
(Sum of terms)/(number of terms) (10+10+10+2)/4=8
What is the sum of the first multiple of 10?
The sum of 10*1 is 10.
In AP if the 6th and 13th terms are 35 and70 respectively find the sum of its first 20 terms?
We need the common difference to accurately get the first term and then use it to find the sum of the first 20 terms.
What is the sum of the first 10 multiples of 3?
The sum of the first 10 multiples of 3 is 165.
What is average of 10 6 12?
Calculating an average is done in two steps: - First: you calculate the sum of the terms whose average you would like to calculate. - Second: you divide the sum of the terms by their number. In your case: - First: 10 + 6 + 12 = 28 - Second: 28 / 3 = 9.33333.... 3 is the number of terms added together which are: 10, 6 and 12 (3 numbers). Answer: Therefore your average is: 9.33333....
The 7th term of an arithmetic progression is 6 The sum of the first 10 terms is 30 Find the 5th term of the progression?
2
The 'nth term of an Arithmetic Progression is 3n-2.Find the sum of first n terms.What is the sum of first 10 terms?
The sum of the 1st n terms is : N(3N-1)/2 Explanation : The sum from 1 to N of (3m-2) = 3 * sumFrom1toN(m) - sumFrom1toN(2) = 3 * (N*(N+1)/2) -2*N = N(3N-1)/2 For N=10 => 145
Find the sum of the first 48 terms of an aritmetic sequance 2 4 6 8?
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
How do you factor x squared plus 19x plus 90?
Factor as : (x+9)(x+10) using the first terms ( x terms) multiply to x2; the last terms multiply to 90; the sum of 9x + 10 x = 19x
