The sum of the first 100 even numbers is 10,100
The sum of all the first 100 even numbers is 10,100.
37
To find the even two-digit numbers where the sum of the digits is 5, we need to consider the possible combinations of digits. The digits that sum up to 5 are (1,4) and (2,3). For the numbers to be even, the units digit must be 4, so the possible numbers are 14 and 34. Therefore, there are 2 even two-digit numbers where the sum of the digits is 5.
No 5 odd numbers add up to 100. The sum of any two odd numbers is even. The sum of any two even numbers is even. So the sum of any 4 odd numbers must be even. Take that and add an odd number and the sum must be odd. Therefore, the sum of any 5 odd numbers must be odd. 100 is even. In conclusion: The sum of any odd number of odd numbers is odd.
The sum of the first 100 even numbers is 10,100
The sum of all the first 100 even numbers is 10,100.
The sum of the first 5 numbers is 15. 1+2+3+4+5=15
37
2 + 4 + 6 + 8 + 10 = 30 In general, the sum of the first n even numbers is n(n+1). Replacing n with 5 we have 5x6 which equals 30 as we found by direct calcuation. The formula is nice when you have many numbers. For example, finding the sum of the first 100 positive even numbers would be a PAIN! But using the formula is it simply 100x101.
The sum of the first two prime numbers is 5.
The first five prime numbers are 2,3,5,7,11. The sum of the first five prime numbers is 28.The sum is: 2+3+5+7+11 = 28
The sum of the first 1,000,000 positive even numbers is: 2 + 4 + 6 + 8 + ... + 2,000,000 The sum of the first 1,000,000 positive odd integers is: 1 + 3 + 5 + 7 + ... + 1,999,999 The difference between the two is: (2-1) + (4-3) + (6-5) + (8-7) + ... + (2,000,000-1,999,999). This is the same as: 1 + 1 + 1 + 1 + ... + 1. Well how many 1's are there? 1,000,000. So the difference is 1,000,000. Note that if the question asked for the difference between the sum of the first 1,000 positive even numbers and the sum of the first 1,000 positive odd numbers, the answer would be 1,000. The first n even numbers and odd numbers? n.
To find the even two-digit numbers where the sum of the digits is 5, we need to consider the possible combinations of digits. The digits that sum up to 5 are (1,4) and (2,3). For the numbers to be even, the units digit must be 4, so the possible numbers are 14 and 34. Therefore, there are 2 even two-digit numbers where the sum of the digits is 5.
No 5 odd numbers add up to 100. The sum of any two odd numbers is even. The sum of any two even numbers is even. So the sum of any 4 odd numbers must be even. Take that and add an odd number and the sum must be odd. Therefore, the sum of any 5 odd numbers must be odd. 100 is even. In conclusion: The sum of any odd number of odd numbers is odd.
The sum of the first 100 numbers is 5050. The sum of the first 100 even numbers is twice that, so it is 10100 Here is why. Look at the sum of the first 5 numbers, write them as 1 2 3 4 5 and then write them as 5 4 3 2 1 and write the two rows on top of each other. We 5+1 and 4+2 and 3+3 etc. So we have 5 six's and the sum is 5x6, but we wrote them twice, so divide by 2 so the sum is 5X6/2=15 as as we see just by adding them. 1+2+3+4+5=15, Now, look at the first 5 even numbers, 2,4,6,8,10= 30 which is 2 times the first 5 numbers. If we wrote them the same way we wrote the first 5 numbers we have two rows 2,4,6,8,10 and second row 10,,8,6,4,2. We have 5 ( 12)=60, but we counted each number twice, so 60/2=20
The first three odd numbers are 1, 3, and 5. Their sum is 1 + 3 + 5 = 9.