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This can be found out by using the formula for sum of n terms of an arithmetic progression.
here,
n is not known.
a=2
d=2 (since it's even)
nth term=98 (last even number less than 100)
using formula for nth term,
nth term=a+(n-1)d
98=2+(n-1)2
therefore, n=49
so, sum of n terms=n/2[2*a+(n-1)d]
putting n=49, a=2, and d=2,
sum=2450
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