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At which points does the graph of the function y equals x2 plus 4x-12 cross the x-axis?
Wiki User
∙ 14y ago
To determine the x-intercepts, i.e. the roots, of the equation y = x2 + 4x - 12, simply solve the quadratic equation x2 + 4x - 12 = 0.
Recall that the roots of a quadratic equation Ax2 + Bx + C = 0 are given by the solution x = (-B +/- square-root (B2 - 4AC) / 2A.
Plug the coefficients A=1, B=4, and C=-12 into this equation and you get.
x = 4 and X = -12
So the function crosses the X axis at x=4 and x=-12.
Note: If the discriminant, B2 - 4AC, were zero, there would be one real root instead of two. If it were negative, there would be two complex conjugate roots.
Wiki User
∙ 14y ago
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The graph will cross the y-axis once but will not cross or touch the x-axis.
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points
How can you tell if a graph sHow is a function?
Test it by the vertical line test. That is, if a vertical line passes through the two points of the graph, this graph is not the graph of a function.
How can you tell if a graph is a function?
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approaches but does not cross
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