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As asked, there is not enough information to answer your question fully.
It depends upon what you are rolling and with what the sides are labelled.
If you have a tetrahedral die labelled with {0, 1, 0, 1} then the probability is 0.
If you have a tetrahedral die labelled with {3, 4, 3, 4,} then the probability is 1.
If you have a tetrahedral die labelled with {0, 1, 2, 3} then the probability is 1/4.
If you have a tetrahedral die labelled with {1, 2, 3, 4} then the probability is 1/2.
If you have a standard unbiased cube die, then the probability is 1/3.
What else can I help you with?
What is the probability of rolling a 1 2 or 3 on the first roll of a 1-6 number cube and rolling a 4 5 or 6 on the second roll of the same cube?
The probability of (1 or 2 or 3) on the first (or any) roll is 1/2 = 50% .The probability of (4 or 5 or 6) on the second (or any) roll is 1/2 = 50% .The probability of exactly that result on two rolls is (1/2 x 1/2)= (50% x 50%) = 1/4 = 25% .
What is the theoretical probability of rolling a factor of 6 on a die?
When rolling a die, a 1, or a 2, or a 3, or a 4, or a 5, or a 6 will come up. Factors of six are 1, 2, 3 and 6. This leaves 4 and 5 that are not factors of 6. The probability of rolling any one number in one roll of the die is 1 in 6, or 1/6. To find a "cumulative" probability where we "combine" the odds of rolling several numbers, as is the case here, we simply add the probability of rolling each number together and sum them.In the case here, the probability of rolling 1 is 1/6, and the probability of rolling 2 is also 1/6, and the probability of rolling 3 is 1/6 and the probability of rolloing 6 is 1/6. We add 1/6 + 1/6 + 1/6 + 1/6 and get 1+1+1+1/6, which is 4/6. The 4/6 reduces to 2/3, and that 2/3 represents the probability of rolling a factor of 6 with one roll of a die. There is one more little thing.Probability is a mathematical term where "odds" are expressed on a scale of zero (0) to one (1). The probability of something happening is either 0, or 1, or something in between. If the probability of something happening is 100% (which is to say that somehting must occur), then the probability is 1. And if something cannot happen, then the probability of it occurring is 0. In this light, the 2/3 chance of rolling a factor of 6 with one roll of a die is 0.6666....
Gary rolls a cube numbered from 1 to 6 What is the probability that he will not roll an even number greater than 3?
Gary's chances of rolling either a 4 or a 6 are the same for any of the other numbers on the cube. The probability is 1 out of 3.
What is the probability that you will spin a 4 and roll a 4?
Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60
What is the probability of getting one 6 in 4 rolls of a die?
The probability of 1 roll of 4 rolls of a die being 6 is: 1/6 x 5/6 x 5/6 x 5/6 = 125/1296 However, that one roll could be the first, second, third or fourth roll, so the total probability is 4 times this: Pr(one 6 on 4 rolls of 1 die) = 4 x 125/1296 = 125/324 ≈ 0.385
What is the theoretical probability of rolling 3 or a 4 on a number cube?
1/3
What is the probability of rolling a sum of 4 using a die?
If you roll a single die (cube), the probability of a 4 is 1/6 or 162/3%. If you roll a pair of dice (2 cubes), the probability of a 4 is 1/12 or 82/3%.
What are the odds of getting 1 2 3 4 5 6 if you roll one six sided dice?
1/6 for all 6 numbers.-- On the first roll, the probability of a ' 1 ' is 1/6 .-- On the second roll, the probability of a ' 2 ' is 1/6 .-- On the third roll, the probability of a ' 3 ' is 1/6 .-- On the fourth roll, the probability of a ' 4 ' is 1/6 .-- On the fifth roll, the probability of a ' 5 ' is 1/6 .-- On the sixth roll, the probability of a ' 6 ' is 1/6 .So the probability of rolling 1 - 2 - 3 - 4 - 5 - 6 in six rolls is (1/6)6 = 0.000021433 = 0.0021%
What is the theoretical probability of not rolling factors of 5 on a die?
It is 4/6 = 2/3
If you roll a dice twice what is the theoretical probability of rolling three then four?
On a normal 6 sided dice the probability of rolling any number is 1/6.When we want a 3 AND then a 4 we multiply the probabilities together.So P(3 then 4) = 1/6 x 1/6 = 1/36
Theoretical probability that a family of 4 children will be all girls?
4/6=2/4 n(s)=3 6
What is the probability of rolling a 5 on the first roll or a 4 on the second roll?
1/6 + 1/6 = 1/3
When is theoretical less than the experimental?
theoretical probability can be smaller than expiremental like this say you toss a coin 4 times it lands on head 3 times that means the theoretical 1/2 is now smaller than the expiremental 3/4
What is the probability you will roll a 3 and a 4 on 2 dice at the same time?
Assuming they are fair, regular dice, the probability is 1/18.
What is the probability of rolling a 1 2 or 3 on the first roll of a 1-6 number cube and rolling a 4 5 or 6 on the second roll of the same cube?
The probability of (1 or 2 or 3) on the first (or any) roll is 1/2 = 50% .The probability of (4 or 5 or 6) on the second (or any) roll is 1/2 = 50% .The probability of exactly that result on two rolls is (1/2 x 1/2)= (50% x 50%) = 1/4 = 25% .
Six-sided die is rolled What is the probability that either a 3 or 4 is rolled?
It can roll on 1,2,3,4,5,6 so the probability of 2/6 is ±33.33%
What is the probability of rolling a number less than 3 and greater than 4 with one roll of a number cube?
The probability is zero. No number can be less than 3 and greater than 4.
