Plug in any value for x (they may be given) and calculte y. For example, if you are given 3 for x then y is 1.
(y2-y1)/(x2-x1) y=mx+b
A specific ordered pair is (1,3) or (-1000,398), an arbitrary one is (x,y) or (x1 ,x2 ). This means we do not specify and particular number.
x2 + x2 = 2x2
There are infinitely many possible equations. The simplest is y = (x2 + 11x - 2)/2
70.50
Y2-y1 x2-x1
(y2-y1)/(x2-x1) y=mx+b
The y-values for the two ordered pairs would have to be the same (for example, (3,1) and (6,1) would be such a set of ordered pairs). Because the slope of a line is (y1-y2)/(x1-x2), for the slope to be zero, y1=y2.
A specific ordered pair is (1,3) or (-1000,398), an arbitrary one is (x,y) or (x1 ,x2 ). This means we do not specify and particular number.
x2 + x2 = 2x2
There are infinitely many possible equations. The simplest is y = (x2 + 11x - 2)/2
x1:y1 = x2:y2 4:-2 = x2:5 x2 = (4*5)/-2 x2 = -10
x2 23x equals 0
The ordered pairs that fit this situation are (2,4) and (4,16), where the first number represents the side length of the square and the second number represents the area of the square.
add 3 to both sides x2 -3(+3) =162 (+3) x2 = 165 x ~ +- 12.84
x2≤64
if c = x2 then cx2 = x4