(y2-y1)/(x2-x1) y=mx+b
A specific ordered pair is (1,3) or (-1000,398), an arbitrary one is (x,y) or (x1 ,x2 ). This means we do not specify and particular number.
x2 + x2 = 2x2
There are infinitely many possible equations. The simplest is y = (x2 + 11x - 2)/2
70.50
Y2-y1 x2-x1
(y2-y1)/(x2-x1) y=mx+b
The y-values for the two ordered pairs would have to be the same (for example, (3,1) and (6,1) would be such a set of ordered pairs). Because the slope of a line is (y1-y2)/(x1-x2), for the slope to be zero, y1=y2.
A specific ordered pair is (1,3) or (-1000,398), an arbitrary one is (x,y) or (x1 ,x2 ). This means we do not specify and particular number.
x2 + x2 = 2x2
There are infinitely many possible equations. The simplest is y = (x2 + 11x - 2)/2
x1:y1 = x2:y2 4:-2 = x2:5 x2 = (4*5)/-2 x2 = -10
The ordered pairs that fit this situation are (2,4) and (4,16), where the first number represents the side length of the square and the second number represents the area of the square.
x2 23x equals 0
add 3 to both sides x2 -3(+3) =162 (+3) x2 = 165 x ~ +- 12.84
I assume you are talking about the ordered pair (0, 2) and (5,3). The slope formula is y2-y1 / x2-x1 Ordered pairs are in the form (x, y) so x1 is 0 and x2 is 5 and y1 is 2 and y2 is 3. Someone told you the wrong thing before
It equals x2 - 34