Plug in any value for x (they may be given) and calculte y. For example, if you are given 3 for x then y is 1.
(y2-y1)/(x2-x1) y=mx+b
A specific ordered pair is (1,3) or (-1000,398), an arbitrary one is (x,y) or (x1 ,x2 ). This means we do not specify and particular number.
x2 + x2 = 2x2
There are infinitely many possible equations. The simplest is y = (x2 + 11x - 2)/2
Substitute the value for y given by the second equation into the first equation to result in 3x - 15 = x2 - x -20. Subtract (3x - 15) from both sides and exchange sides to yield x2 - 4x - 5 = 0. This can be factored into (x - 5)(x + 1) = 0, which is true when x equals either 5 or -1. If x = 5, y = 0 and if x = -1, then y = -18. Therefore, either 5,0 or -1,-18 is an ordered pair solution to the given equation system.
Y2-y1 x2-x1
(y2-y1)/(x2-x1) y=mx+b
To find the average between two ordered pairs, you calculate the average of their corresponding coordinates. For example, if you have the pairs (x1, y1) and (x2, y2), the average pair is given by ((\frac{x1 + x2}{2}, \frac{y1 + y2}{2})). This results in a new ordered pair that represents the midpoint between the two given points in a Cartesian coordinate system.
The y-values for the two ordered pairs would have to be the same (for example, (3,1) and (6,1) would be such a set of ordered pairs). Because the slope of a line is (y1-y2)/(x1-x2), for the slope to be zero, y1=y2.
A specific ordered pair is (1,3) or (-1000,398), an arbitrary one is (x,y) or (x1 ,x2 ). This means we do not specify and particular number.
x2 + x2 = 2x2
There are infinitely many possible equations. The simplest is y = (x2 + 11x - 2)/2
x1:y1 = x2:y2 4:-2 = x2:5 x2 = (4*5)/-2 x2 = -10
The ordered pairs that fit this situation are (2,4) and (4,16), where the first number represents the side length of the square and the second number represents the area of the square.
x2 23x equals 0
add 3 to both sides x2 -3(+3) =162 (+3) x2 = 165 x ~ +- 12.84
I assume you are talking about the ordered pair (0, 2) and (5,3). The slope formula is y2-y1 / x2-x1 Ordered pairs are in the form (x, y) so x1 is 0 and x2 is 5 and y1 is 2 and y2 is 3. Someone told you the wrong thing before