Plug in any value for x (they may be given) and calculte y. For example, if you are given 3 for x then y is 1.
(y2-y1)/(x2-x1) y=mx+b
A specific ordered pair is (1,3) or (-1000,398), an arbitrary one is (x,y) or (x1 ,x2 ). This means we do not specify and particular number.
x2 + x2 = 2x2
There are infinitely many possible equations. The simplest is y = (x2 + 11x - 2)/2
70.50
Y2-y1 x2-x1
(y2-y1)/(x2-x1) y=mx+b
The y-values for the two ordered pairs would have to be the same (for example, (3,1) and (6,1) would be such a set of ordered pairs). Because the slope of a line is (y1-y2)/(x1-x2), for the slope to be zero, y1=y2.
A specific ordered pair is (1,3) or (-1000,398), an arbitrary one is (x,y) or (x1 ,x2 ). This means we do not specify and particular number.
x2 + x2 = 2x2
There are infinitely many possible equations. The simplest is y = (x2 + 11x - 2)/2
Y = x2
x1:y1 = x2:y2 4:-2 = x2:5 x2 = (4*5)/-2 x2 = -10
x2 23x equals 0
add 3 to both sides x2 -3(+3) =162 (+3) x2 = 165 x ~ +- 12.84
I assume you are talking about the ordered pair (0, 2) and (5,3). The slope formula is y2-y1 / x2-x1 Ordered pairs are in the form (x, y) so x1 is 0 and x2 is 5 and y1 is 2 and y2 is 3. Someone told you the wrong thing before
It equals x2 - 34