x2 = 64
82 = 64
x = 8
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To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
X2 = 64take square root each sideX = 8====
Assuming that by expressing that equation as a question you're looking to solve for x: x2 - 4x - 29 = -10 x2 - 4x + 4 = 23 (x - 2)2 = 23 x - 2 = ± √23 x = 2 ± √23
x2 + 2x - 13 = 2 x2 + 2x - 15 = 0 (x + 5)(x - 3) = 0 x + 5 = 0 and x - 3 = 0 so x = -5 and x = 3
X = 8 x2 (8)2 = 64 ====
x2≤64
x2-64 = (x-8)(x+8)
x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
x: x2 - 81 = 0
8
x2 - 10x + 25 = 64 Or x2 - 10x + 25 = 64? If the first, move all over to 1 side; x2 - 10x + 25 - 64 = 0 x2 - 10x + -39 = 0 Then make it into quadratic equations; (x - 13)(x + 3) = 0 Therefore x = 13 or x = -3. If the second, 8x = -39 -39/8 = -9.75 = x
x=18
64 + x2 = 196 Therefore, 196 - x2 = 64 x2 = 132 Therefore, x = sqrt(132). Rounded to three decimal places, this is equal to 11.489.
x2 + 12x - 64 = 0 ∴ (x + 16)(x - 4) = 0 ∴ x ∈ {4, -16}
If x = 8 then x2 = 82 = 8 x 8 = 64
8
This type of expression is referred to as a difference of squares. Any expression in the format: a2 - b2 Can be expanded as: (a + b)(a - b) In this case then, we have: x2 - 64 = 0 (x + 8)(x - 8) = 0 This tells us that x must be equal to either 8 or -8.