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What is the total number of candidates at an examination if 31 percent fails and the number of those who pass exceeds the number of those who fail by 247?
Wiki User
∙ 11y ago
31% fail so 100-31 = 69% pass.The percentage of those who pass exceeds the percentage of those who fail by 69-31 = 38%
So 38% = 247
which means that 100% = 100*247/38 = 650 candidates.
31% fail so 100-31 = 69% pass.The percentage of those who pass exceeds the percentage of those who fail by 69-31 = 38%
So 38% = 247
which means that 100% = 100*247/38 = 650 candidates.
31% fail so 100-31 = 69% pass.The percentage of those who pass exceeds the percentage of those who fail by 69-31 = 38%
So 38% = 247
which means that 100% = 100*247/38 = 650 candidates.
31% fail so 100-31 = 69% pass.The percentage of those who pass exceeds the percentage of those who fail by 69-31 = 38%
So 38% = 247
which means that 100% = 100*247/38 = 650 candidates.
Wiki User
∙ 11y ago
Wiki User
∙ 11y ago31% fail so 100-31 = 69% pass.The percentage of those who pass exceeds the percentage of those who fail by 69-31 = 38%
So 38% = 247
which means that 100% = 100*247/38 = 650 candidates.
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