The sum of whole numbers 1 through 30 is 465.
(30 + 1) * 30/2 ie 465
The product of a sum and a difference with 31 times 29 is:(30+1) x (30-1)sum to differencemakea product= 30² - 1²= 900 - 1= 899
465
Oh, dude, math time! So, if 30% of the sum is 750, we can figure out the whole sum by doing some basic math. We just divide 750 by 0.30 to find out the total sum, which comes out to be 2500. So, the sum of money is 2500 bucks. Math made easy, like a piece of cake... or pie.
The sum of whole numbers 1 through 30 is 465.
#include <iostream> using namespace std; int main() { int i,sum; // variables sum = 0; // initialize sum /* recursive addition of squares */ for (i = 1; i <= 30; i++) sum = sum + (i * i); cout << sum <<" is the sum of the first 30 squares." << endl; return 0; }
(30 + 1) * 30/2 ie 465
The product of a sum and a difference with 31 times 29 is:(30+1) x (30-1)sum to differencemakea product= 30² - 1²= 900 - 1= 899
The two numbers are 5 and -6. 5x(-6) = -30 so the product is -30 and 5+(-6) = -1 so the sum is -1
465
Oh, dude, math time! So, if 30% of the sum is 750, we can figure out the whole sum by doing some basic math. We just divide 750 by 0.30 to find out the total sum, which comes out to be 2500. So, the sum of money is 2500 bucks. Math made easy, like a piece of cake... or pie.
1+30=31 and 1x30=30
3/10 + 1/3... = 9/30 + 10/30... = 19/30
29 and 30.
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
sum -10 to -1 = -55; sum 1 to 2,012 = 2,013 x 1,006 = 2,025,078 total 2,025,023