Height of side = square root of (625 cm2 + 196 cm2) = 28.65 cm Surface area of 4 sides = 4 x 28.65 cm x 14 cm = 1,604 cm2 Area of base = 196 cm2 Total surface area, including area of base, is 1,800 cm2
Call the length of the base s and the slant height of one triangle l SA = s2 + 2sl
429 m
The slant height of a square pyramid is always perpendicular to the base. It is form the top vertex all the way down to the most center of one side of the base edge.
A pyramid with these measurements are technically impossible to construct. However if you follow the formula the surface area would be a negative amount.
If you make a line from the top of the pyramid to the center of the base, you have the height of the pyramid. This meets at the midsegment of a line going across the base. Since the height of a pyramid is perpendicular with the base, get this: the height, a line of 1/2 the length of the base, and the slant height form a right triangle. So, you can use the Pythagorean Theorem! For example, if the base length is 6 and the height of the pyramid is 4, then you can plug them into the Pythagorean Theorem (a squared + b squared = c squared, a and b being the legs of a right triangle and c being the hypotenuse). 1/2 the length of the base would be 6 divided by 2=3. 3 squared + 4 squared = slant height squared. 9+16=slant height squared. 25= slant height squared. Slant height=5 units. You're welcome!
120
72 cm square.
It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.
Call the length of the base s and the slant height of one triangle l SA = s2 + 2sl
It is 9180900 square inches.
The height would be The square root of the square of the slant surface length minus the square of the radius of the cone at the base.
It is 448 square cm.
Such a pyramid cannot exist. If it is a regular pyramid with side length 8, its slant height MUST be less than 8. In fact, it is approx 6.39.
Slant height is 39.98 cm
Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.
For a rectangular pyramid (which is not a square bottom) you can not use the standard formula of Surface Area = B + 1/2 * P * s, because there is more than one slant height.A rectangular pyramid is made up of 1 rectangular baseand 4 triangles going up from the base to the top of the pyramid. The surface area is the area of all five parts added togetherThe first bit is a rectangle so you can find the area of it by multiplying its length times its width.Now we have four triangles, two of them will have a base which is the length of the pyramid and two will have a base which is the width of the pyramid.The area of a triangle is (1/2*bh), where b is the base (either length of width of the rectangle) and h is the slant height (distance from the base to the top of the pyramid).The triangles with base = length and the triangles with base = height will have different slant heights. There will be two triangles of each type so the area of all four triangles will be 2(1/2*ls1) + 2(1/2*ws2) = l*s1 + w*s2If you have been given both slant heights you have enough information to answer the question at this stage,You will have SA = l*w + l*s1 + w*s2(where l is length, w is width, s1 is the slant length of the triangles with base l, s2 is the slant length of the triangles with base w)If you do not have the slant lengths you will have to use the Pythagorean Theorem to find them, this will tell you the slant length of the triangle with base l, will be the square root of (w/2)2 + h2 where h is the height of the pyramid (distance from bottom to top through middle of pyramid) similarly the slant length of the triangle with base w will be the square root of (l/2)2 + h2