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What is the total surface area of a square pyramid that has a base length of 14 cm and the slant length is 25 cm?
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What is the formula for the surface area of a square pyramid?
Call the length of the base s and the slant height of one triangle l SA = s2 + 2sl
The square base of pyramid has a side length of 230 m and the sides of the Pyramid meet the base at an angle which measuresapproximately 60 What is the sum of the height and slant height?
429 m
What is the slant height of a square pyramid?
The slant height of a square pyramid is always perpendicular to the base. It is form the top vertex all the way down to the most center of one side of the base edge.
What is a total area of a pyramid that has a square base with sides 8 and a slant height of 5?
A pyramid with these measurements are technically impossible to construct. However if you follow the formula the surface area would be a negative amount.
How do you find the slant height of a pyramid with a rectangular base?
If you make a line from the top of the pyramid to the center of the base, you have the height of the pyramid. This meets at the midsegment of a line going across the base. Since the height of a pyramid is perpendicular with the base, get this: the height, a line of 1/2 the length of the base, and the slant height form a right triangle. So, you can use the Pythagorean Theorem! For example, if the base length is 6 and the height of the pyramid is 4, then you can plug them into the Pythagorean Theorem (a squared + b squared = c squared, a and b being the legs of a right triangle and c being the hypotenuse). 1/2 the length of the base would be 6 divided by 2=3. 3 squared + 4 squared = slant height squared. 9+16=slant height squared. 25= slant height squared. Slant height=5 units. You're welcome!
What is the surface area of a square pyramid when 4 is the side length and 13 as the slant height?
120
What is the lateral surface area of this square pyramid that has a base length of 4 centimeters and a slant height of 9 centimeters?
72 cm square.
What is the surface area of the right square pyramid in square meters?
It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.
What is the formula for the surface area of a square pyramid?
Call the length of the base s and the slant height of one triangle l SA = s2 + 2sl
The pyramid shown has a square base that is 1818 inches on each side. The slant height is 1616 inches. What is the surface area of the pyramid?
It is 9180900 square inches.
What is the surface area of the square pyramid shown if the base has a side length of 8 inches and l 15 inches?
To calculate the surface area of a square pyramid, you need to find the area of the base (which is a square) and the area of the four triangular faces. The formula for the surface area of a square pyramid is SA = s^2 + 2sl, where s is the side length of the base and l is the slant height. In this case, with a base side length of 8 inches and a slant height of 15 inches, the surface area would be SA = 8^2 + 2(8)(15) = 64 + 240 = 304 square inches.
How do you find the height of a cone if you have the slant height and the diameter?
The height would be The square root of the square of the slant surface length minus the square of the radius of the cone at the base.
What is the lateral area of a square pyramid with side length 11.2 cm and slant height 20 cm?
It is 448 square cm.
What is the surface area of a regular pyramid with side length 8 and slant height 9 the number of the side of the base is given by 3?
Such a pyramid cannot exist. If it is a regular pyramid with side length 8, its slant height MUST be less than 8. In fact, it is approx 6.39.
Find the length of the slant height of a cone with a radius of 15cm and a surface area of 1884cm square?
Slant height is 39.98 cm
What is the lateral area and surface area of a regular square pyramid?
Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
What is the slant height of a pyramid that has all sides as equilateral triangles with sides of length of 9 cm and the surface area of the pyramid is 140.4 square cm?
The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.
