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To find the units digit of 399 the question being asked is:

What is (399) MOD 10?

This does not necessitate evaluation of 399 before the modulus is done, as it can be done whenever it is possible during the multiplication as any multiple of 10 multiplied by 3 is still a multiple of 10.

The first few powers of 3 modulus 10 are:

31 MOD 10 = 3

32 MOD 10 = (3 x 31) MOD 10 = (3 x 3) MOD 10 = 9

33 MOD 10 = (3 x 32) MOD 10 = (3 x 9) MOD 10 = 27 MOD 10 = 7

34 MOD 10 = (3 x 33) MOD 10 = (3 x 7) MOD 10 = 81 MOD 10 = 1

35 MOD 10 = (3 x 34) MOD 10 = (3 x 1) MOD 10 = 3

36 MOD 10 = (3 x 35) MOD 10 = (3 x 3) MOD 10 = 9

At this point, it can be seen that the answer is a repeating pattern of 3, 9, 7, 1, 3, 9, ...

So we need the 99th element of this pattern.

The pattern is a repeat of 4 digits, so we calculate 99 MOD 4 = 3. So the 3rd element of the repeating part is the answer: 7.

(If the power MOD 4 had been 0, it would have been the 4th element of the pattern: 1)

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Q: What is the unit digit in 3 power 99?
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How do you find the unit digit of 3127 power 173?

The unit digit of 3127173 is the unit digit of 7173. The other digits of 3127 are multiples of 10 and so they cannot contribute to the unit digit. Now the unit digits of the powers of 7 are Power -- Unit digit 0 -- 1 1 -- 7 2 -- 9 3 -- 3 4 -- 1 and you are back into the loop (of 1-7-9-3). So, you only need consider 7 to the power 173 modulo 4. That is, the remainder when 173 is divided by 4. 173 = 1 mod 4 So the unit digit of 3127173 is the same as the unit digit of 7173 which is the unit digit of 71 which is 7.


What is the predecessor of 3 digit number?

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What is the unit digit in the sum of first 99 whole numbers?

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If you add a two digit number to a two digit number do you get a four digit number?

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