1 divided by n has an infinite amount of values, and the only restriction is n cannot equal 0 (because 1/0 is undefined).
If we write this as a function:
f(n) = 1/n
A few values are:
f(1/4) = 1/(1/4) = 4
f(1/2) = 1/(1/2) = 2
f(1) = 1/1 = 1
f(2) = 1/2
f(4) = 1/4
If you mean: n/5 = 64/40 then the value of n is 8
lim(n->infinity)(1+1/n)^n
1
N=4.
/* note that neither of these functions have been tested, so there may be typos and the like *//* if you're looking to return a real value: */unsigned int complement(unsigned int value){unsigned int returnvalue = 0;while(value){returnvalue = 1;}return returnvalue;}/* if you're looking for a string representing the binary number: */char *complement(unsigned int value){int numchars = 8 * sizeof(unsigned int);int n;char *returnvalue = malloc((numchars + 1) * sizeof(char));for(n = 0; n < numchars; n++){if(value & (1
It is an equation and the value of n is 5 Therefore: I/10 = 1/10
Future Value = Value (1 + t)^n Present Value = Future Value / (1+t)^-n
lim(n->infinity)(1+1/n)^n
The answer depends on the value of n.
what is the value of "N"? we can solve this equation when we know the value of N, once we know the value of N we just add 1 to it,
Use Guassian quadrature with n=1 and n=2 and compare to exact value I=
The magnetic quantum number value for an element with n=1 is the K shell.
1
The question is ambiguous. Does "2 over 3 times n" mean 2/(3*n) or (2/3)*n
The most probable rules for generating this series seems to be that for n = 1, the value is 60, and for any other positive integral value of n, the value (Vn) is [(n - 1)(V(n - 1))/n]. If this is the actual rule, the next number is 10.
n _ 1 6 6 = (n-1) 6
N=4.