1 divided by n has an infinite amount of values, and the only restriction is n cannot equal 0 (because 1/0 is undefined).
If we write this as a function:
f(n) = 1/n
A few values are:
f(1/4) = 1/(1/4) = 4
f(1/2) = 1/(1/2) = 2
f(1) = 1/1 = 1
f(2) = 1/2
f(4) = 1/4
If you mean: n/5 = 64/40 then the value of n is 8
1
N=4.
Future Value = (Present Value)*(1 + i)^n {i is interest rate per compounding period, and n is the number of compounding periods} Memorize this.So if you want to double, then (Future Value)/(Present Value) = 2, and n = 16.2 = (1 + i)^16 --> 2^(1/16) = 1 + i --> i = 2^(1/16) - 1 = 0.044274 = 4.4274 %
/* note that neither of these functions have been tested, so there may be typos and the like *//* if you're looking to return a real value: */unsigned int complement(unsigned int value){unsigned int returnvalue = 0;while(value){returnvalue = 1;}return returnvalue;}/* if you're looking for a string representing the binary number: */char *complement(unsigned int value){int numchars = 8 * sizeof(unsigned int);int n;char *returnvalue = malloc((numchars + 1) * sizeof(char));for(n = 0; n < numchars; n++){if(value & (1
It is an equation and the value of n is 5 Therefore: I/10 = 1/10
If you mean: n/5 = 64/40 then the value of n is 8
Future Value = Value (1 + t)^n Present Value = Future Value / (1+t)^-n
The answer depends on the value of n.
If you mean: 6/n times 5/n-1 = 1/3 Then: 30/n2-n = 1/3 Multiplying both sides by n2-n: 30 = n2-n/3 Multiplying both sides by 3: 90 = n2-n Subtracting 90 from both sides: 0 = n2-n-90 or n2-n-90 = 0 Solving the above quadratic equation: n = -9 or n =10 If n is of a material value its more likely to be 10 Note that n2 means n squared
what is the value of "N"? we can solve this equation when we know the value of N, once we know the value of N we just add 1 to it,
what is the value of "N"? we can solve this equation when we know the value of N, once we know the value of N we just add 1 to it,
what is the value of "N"? we can solve this equation when we know the value of N, once we know the value of N we just add 1 to it,
n/n = 1, irrespective of the value of n.
n = 8
The value of the expression n(n-1)(n-2)(n-3)(n-4)(n-5) is the product of n, n-1, n-2, n-3, n-4, and n-5.
Use Guassian quadrature with n=1 and n=2 and compare to exact value I=