It is the exponential series of 2, or 2n but offset by one value.
3 x10 30 x10
3
It is: 2 to the power of 8 = 256
2
The one line expression is: ((0 != n) && !(n & n-1)) example: int main () { for (int n = 0; n <= 1000001; ++n) { if ((0 != n) && !(n & n-1)) cout << n << " is a power of 2" << endl; } return 0; } will produce: 1 is a power of 2 2 is a power of 2 4 is a power of 2 8 is a power of 2 16 is a power of 2 32 is a power of 2 64 is a power of 2 128 is a power of 2 256 is a power of 2 512 is a power of 2 1024 is a power of 2 2048 is a power of 2 4096 is a power of 2 8192 is a power of 2 16384 is a power of 2 32768 is a power of 2 65536 is a power of 2 131072 is a power of 2 262144 is a power of 2 524288 is a power of 2
It is the exponential series of 2, or 2n but offset by one value.
3^n+2+3^n = 6^n+2 *'to the power of' can be represented with this symbol ^ .
n is the no. so therefore a n value is the numerical or fix value e.g. 7^n, where n is 2 your result will be 49.
puts ("32"); /*or*/ printf ("2^5=%d\n", 1<<5);
16(2^n)(10)(2^n)=160[2^(2n)]=160(4^n)
Assume 2^k < k! for all n > k here n > 2, then 2^n = 2^(n - 1)*2 < (n-1)! * n = n! Done. Connie and John
The value of 4 to the power of -2 is 0.0625
N+2
n is the no. so therefore a n value is the numerical or fix value e.g. 7^n, where n is 2 your result will be 49.
1proof:n**3 * n**-3 = n**0n**3 = n*n*nn**-3 = 1/n * 1/n * 1/n1/n * 1/n * 1/n * n * n * n= n*n*n/(n*n*n) = 1Any number to the zero power = 1 .Any number to the ' 1 ' power = itself .Also:ex. 3^0 = 1but this is also the same value as :5^0 = 1Hence 3^0 = 5^0 = n^0 = 1If you had 3^2 / 3^2 the result is 1 since any value divided by itself it 1.Hence the base (here it's 3) and the exponent (here it's 2) is essentially eliminated and the result is just 1 as it would be for any other base and exponent. Mathematically, in an expression form you can eliminate (set to 0) the exponent by subtracting the exponents:3^2 / 3^2 = 1 = 3^(2-2) = 3^0 = 1 = n^0X^0=1How about this:If you had 5^2 / 5^2 , it equal 1 since any number divided by that same value is one. Therefore there is no power of 5 left since 5^1 would be 5. It is as if you subracted the exponents: 5^(2-2) = 5^0. This is valid because if you had something like:5^2 / 5^1 = 5^(2-1) = 5^125 / 5 = 5 = 5^1
It is twice as great.