Place value: hundredsFace value: three hundred.Place value: hundredsFace value: three hundred.Place value: hundredsFace value: three hundred.Place value: hundredsFace value: three hundred.
Find the value of the fraction.Find the value of the fraction.Find the value of the fraction.Find the value of the fraction.
the value of 6 is 60 000 the value of 7 is 7000 the value of 2 is 200 the value of 4 is 40 the value of 1 is 1
The value is 300.
The answer depends on the value of WHAT! The value of your degree education or the value of your student loan debt!
6*5*4=120
The electron configuration of Polonium, atom number 84, is:In shells n=1 to 6:2, 8, 18, 32, 18, 6In subshells:1s2, 2s2 2p6, 3s2 3p6, 4s2 3d10 4p6, 5s2 4d10 5p6, 6s2 4f14 5d10 6p4or in shorthand: [Xe] 6s2 4f14 5d10 6p4
The condensed electron configuration of polonium is [Xe] 6s^2 4f^14 5d^10 6p^4.
Polonium is a Group 16 element in the p-block of the periodic table. It has a valence shell of 6s26p4, so it has six valence electrons like all of the elements of Group 16 (16-10=6 valence electrons). To write the Lewis dot diagram for polonium, write the symbol for polonium, Po. Then place one electron on each side of the symbol, then place another electron on two sides. You should have two electrons on two sides of the symbol, and one electron on two sides of the symbol. The total number of electrons should be six.
Electron_configuration[Xenon] 6s2 4f14 5d10 6p4Electron_configuration[Xenon] 6s2 4f14 5d10 6p4
6P4 = 6!/(6-4)! = 6 * 5 * 4 * 3 = 360 four letter permutations from 6 different letters.6C4 = 6!/[4!∙(6-4)!] = 15 four letter combinationsfrom 6 different letters.
No, Xe 6s2, 5d10, 6p4 , this is not ground state of any Xe descendant.In fact it is an impossible electron configuration, because the 4f-block is missing, which should be filled in before 6p block at the 'end' of the 6throw,so it even isn't 84Po [Xe] 6s2 4f14 5d10 6p4 .Xenon ground state is in short note: [Kr] 5s2 4d105p6In full: [1s2, 2s2 2p6, 3s2 3p6 3d10, 4s2 4p6] 5s2 4d10 5p6Radon ground state is in short note: [Xe] 6s2 4f145d10 6p6In full: [1s2, 2s2 2p6, 3s2 3p6 3d10 3f14, 4s2 4p6 4d10, 5s2 5p6] 6s2 4f14 5d10 6p6
The electron configuration of Polonium, atom number 84, is:In shells n=1 to 6:2, 8, 18, 32, 18, 6In subshells:1s2, 2s2 2p6, 3s2 3p6, 4s2 3d10 4p6, 5s2 4d10 5p6, 6s2 4f14 5d10 6p4or in shorthand: [Xe] 6s2 4f14 5d10 6p4
Place value: hundredsFace value: three hundred.Place value: hundredsFace value: three hundred.Place value: hundredsFace value: three hundred.Place value: hundredsFace value: three hundred.
To increment a value by 1, you have 4 choices:value++;++value;value += 1;value = value + 1;Pre and post processing incrementation/decrementation refers to the first two: ++value and value++.Both do exactly the same, as both will increase the value of 'value' by one.If we have a situation like this:int value = 0;int value1 = 0;value1 = value++;This essentially means:value1 = value;value = value + 1;Where ++value means:value = value + 1;value1 = value;
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