If you mean: n2+16n+64 then it is (n+8)(n+8) when factored
n= sqrt 225 = 15
Conditional statement: If n2 equals 64, then n equals 8, where n2 equals 64 is the hypothesis, and n equals 8 is the conclusion. In order to obtain the converse of the conditional we reverse the 2 clauses, then the original conclusion becomes the new hypothesis and the original hypothesis becomes the new conclusion. So that, Converse: If n equals 8, then n2 equals 64.
n x n = n2
n3 + 1 = n3 + 13 = (n + 1)(n2 - n + 12) = (n + 1)(n2 - n + 1)
If you mean: n2+16n+64 then it is (n+8)(n+8) when factored
n=40 n2+n+41=1681 which is not a prime.
38.The position to value rule is Un= (n2+ 7n - 2)/2 where n = 1, 2, 3, ...38.The position to value rule is Un= (n2+ 7n - 2)/2 where n = 1, 2, 3, ...38.The position to value rule is Un= (n2+ 7n - 2)/2 where n = 1, 2, 3, ...38.The position to value rule is Un= (n2+ 7n - 2)/2 where n = 1, 2, 3, ...
n= sqrt 225 = 15
If you mean: 6/n times 5/n-1 = 1/3 Then: 30/n2-n = 1/3 Multiplying both sides by n2-n: 30 = n2-n/3 Multiplying both sides by 3: 90 = n2-n Subtracting 90 from both sides: 0 = n2-n-90 or n2-n-90 = 0 Solving the above quadratic equation: n = -9 or n =10 If n is of a material value its more likely to be 10 Note that n2 means n squared
Let the number of sweets be n and use the rules of probability:- If: 6/n times 5/n-1 = 1/8 Then: 30/n2-n = 1/8 Multiplying both sides by n2-n: 30 = n2-n/8 Multiplying both sides by 8: 240 = n2-n Subtracting both sides by 240: 0 = n2-n-240 Solving the above quadratic equation: n = 16 or n = -15 Therefore it follows: n = 16 sweets Note that n2 means n squared
Conditional statement: If n2 equals 64, then n equals 8, where n2 equals 64 is the hypothesis, and n equals 8 is the conclusion. In order to obtain the converse of the conditional we reverse the 2 clauses, then the original conclusion becomes the new hypothesis and the original hypothesis becomes the new conclusion. So that, Converse: If n equals 8, then n2 equals 64.
n is 2. To solve, do the division: . . . . . . . . .x2 +. 3x + (6-2n) . . . -------------------------- x-2 | x3 + x2 - 2nx + n2 . . . . .x3 -2x2 . . . . .-------- . . . . . . . .3x2 - 2nx . . . . . . . .3x2 - . 6x . . . . . . . .---------- . . . . . . . . . (6-2n)x + n2 . . . . . . . . . (6-2n)x - 2(6-2n) . . . . . . . . . ---------------------- . . . . . . . . . . . . . . . .n2 + 2(6-2n) But this remainder is known to be 8, so: n2 + 2(6-2n) = 8 ⇒ n2 - 4n + 4 = 0 ⇒ (n - 2)2 = 0 ⇒ n = 2
That depends on the value of "n". n2 (n squared) simply means "n" times "n".
The formula can be written, with "n" representing a number or value, as n2 or n X n.
n x n = n2
The hybridization of N i n N2 is sp.