Factors of x5 . . . 1, x, x2, x3, x4, and x5, as well as any factors of 'x', and their powers.
Factors of y5 . . . 1, y, y2, y3, y4, and y5, as well as any factors of 'y', and their powers.
2y2-2y-4 = (2y-4)(y+1) when factored
1, 5, 7, 35, y, x
99 = 318 = 276 etc.
x2 - y2 = 16 then (x + y)*(x - y) = 16 This has an infinite number of solutions lying on the hyperbola.
Assume we want to factor x³ - y5. There are no possible factors for that expression.
in the English alphabet it is the letter "Y"
-3*-3*-3*x*x*x*y*y = -27x3y2
6x-6y=6(x-y) The factors of 6(x-y) are 6 and (x-y).
There isn't any, and it is quite simple to prove that. Suppose there is a number with the most factors and suppose that number is X. Now consider Y = 2*X. Y has all the factors of X and it has another factor, which is 2. So Y has more factors than X. This contradicts the statement that X has the most factors. Therefore, there is no number with the most factors.
xy + x + y + 1 = (x + 1)(y + 1).
-4
20
It is one number or variable squared subtracted from another Such as x^2-y^2 since this factors as (x-y)(x+y)
16*10*x-16*6*4*x*y = 16*(10*x-6*4*x*y) = 16*2*(5*x-12*x*y) = 32*x*(5-12y) Factors: 32, x, (5-12y)
14x2y does not have any useful factors, but if you want to break it down to completely irreducible terms, that would be: 7 * 2 * x * x * y
There isn't any, and it is quite simple to prove that. Suppose there is a number with the most factors and suppose that number is X. Now consider Y = 2*X. Y has all the factors of X and it has another factor, which is 2. So Y has more factors than X. This contradicts the statement that X has the most factors. Therefore, there is no number with the most factors.
If you meant (45x^4)(y), then the answer is: (3)(3)(5)(x)(x)(x)(x)(y) If you meant 45 times x times 4 times y, then the answer is: (2)(2)(3)(3)(5)(x)(y)