0
You can calculate this by taking the derivative of the equation with respect to x, and solving it for a value of zero:
y = x2 - 2x - 5
∴ dy/dx = 2x - 2
Let dy/dx =0:
0 = 2x - 2
∴ 2x = 2
∴ x = 1
Now you can take that x value and plug it into the original equation to find it's y coordinate:
y = 12 - 2(1) - 5
y = 1 - 2 - 5
y = -6
So the vertex of this parabola occurs at the point (1, -6).
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2
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