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Where is the vertex coordinate of the parabola y equals x square -3x -10 located on the Cartesian plane?
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An equation of a parabola that has x equals 2 as its axis of symmetry is?
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
What is the y-coordinate of the vertex of a parabola with the following equation y equals x2 - 8x plus 18?
You can work this out by taking the derivative of the equation, and solving for zero: y = x2 - 8x + 18 y' = 2x - 8 0 = 2x - 8 x = 4 So the vertex occurs where x is equal to 4. You can then plug that back into the original equation to get the y-coordinate: y = 42 - 8(4) + 18 y = 16 - 32 + 18 y = 2 So the vertex of the parabola occurs at the point (4, 2), leaving 2 as the answer to your question.
What is x squared minus 8x plus 8y plus 32 equals 0 in standard parabola form?
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What are the points of intersection of the lines y equals x4 - 2 and y equals x2?
To find points of intersection of any functions, set them equal to each other: x4-2 = x2 x4-x2-2 = 0 factoring this yields: (x2-2)(x2+1)=0 by the zero identity, each of these factors can be set to zero to yield valid solutions: x2-2 = 0 x2 = 2 x = +/- sqrt(2) the second factor, when set equal to zero, yields an imaginary-valued solution. On a normal Cartesian coordinate plane, this means nothing. I assume you are only looking for points of intersection on a normal, real-valued Cartesian coordinate system (the normal x-y coordinate plane used in most elementary math classes). So, these two functions intersect at x = -sqrt(2) and x = sqrt(2)
What is the x-coordinate of the of the vertex of y equals -3x2 plus 12x-5?
You can find the x-coordinate of it's vertex by taking it's derivative and solving for zero: y = -3x2 + 12x - 5 y' = -6x + 12 0 = -6x + 12 6x = 12 x = 2 Now that we have it's x coordinate, we can plug it back into the original equation to find it's y coordinate: y = -3x2 + 12x - 5 y = -3(2)2 + 12(2) + 5 y = -12 + 24 + 5 y = 17 So the vertex of the parabola y = -3x2 + 12x - 5 occurs at the point (2, 17).
Where is the vertex coordinate of the parabola y equals 24 -6x -3x squared when plotted on the Cartesian plane?
The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.
When x equals 10 y equals 13?
This is a point on the cartesian coordinate plane... (10,13)
Does x equals 0 represent the y axis?
In the two dimensional Cartesian coordinate system, yes.
Any non-vertical line in the Cartesian coordinate plane can be defined by a linear equation of the form y equals ax?
False.
A vertical line in a Cartesian coordinate plane can be defined by a linear equation of the form y equals m x plus b?
false
Would x equals 4 show a horizontal line?
No, in the Cartesian coordinate system it would show a vertical line whose intersection of the x-axis is 4.
What is the parabola fo y equals 4-16y-11?
The equation does not represent that of a parabola.
Is y equals 3x2 -7x plus 2 an up or down parabola?
It is an up parabola.
What are the points of contact of the parabola y equals 6x2 -7x plus 2 makes with the y and x axes on the Cartesian plane?
Parabola: y = 6x^2 -7x+2 It makes contact with the y axis at: (0, 2) It makes contact with the x axis at: (2/3, 0) and (1/2, 0)
What is the parabola y equals -x2-3x plus 2?
It is the parabola such that the coordinates of each point on it satisfies the given equation.
What is the graph of y equals x2-7?
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An equation of a parabola that has x equals 2 as its axis of symmetry is?
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
