0
Add your answer:
Earn +20 pts
What is the value of a Blake and company assayers 20 gold coin from 1855 with a g?
It's a copy of a Blake & Company $20 gold piece. Only 2 authentic coins of this type and date exist. The piece has little or no value.
What is the density of the piece of lead that has a Mass 49.01 g and a volume of 4.5 mL?
220.545
What is the density of a piece of wood that weighs 62 grams and displaces 0.525 l of water?
This is clearly a piece of wood that is forcibly submerged since its density would require it to float. So the volume of displaced water should be equal to the volume of the whole piece of wood. Then, density = mass/volume = 62/0.525 g/L = 62/525 g/ml = 0.12 g/ml which is a lot less dense than balsa (0.16 g/ml)!
What is the density of an object that is mass 15 g volume 2cm3?
Mass = 15 gm Volume = 2 cubic cm Density = Mass/Volume = 15/2 = 7 and 1/2 or 7.5 g per cm3
What is the density of a piece of metal that has a mass of 16g and a volume of 2.8 mL?
Density = Mass/Volume = 16/2.8 g/mL = 5.714 grams per mL (approx).
What is the volume of 2 g a piece of gold?
To calculate the volume of a piece of gold, you need to know its density. Gold has a density of around 19.32 g/cm^3. Using this density value, you can calculate the volume by dividing the mass (2 g) by the density. The volume of 2 g of gold would be approximately 0.104 cm^3.
a piece of gold has a mass of 9.66 g. what is its volume?
ok
What is the volume occupied by 450 g of gold if the density of gold is 19. g per cm3?
The volume of gold can be calculated by dividing the mass by the density. In this case, 450 g divided by 19 g/cm^3 gives a volume of 23.68 cm^3. Therefore, 450 g of gold occupies a volume of 23.68 cm^3.
What is the volume of a piece of magnesium that weighs 2.70 g?
The volume is 1.55 cm^3.
If pure gold has a density of 19.32 gcm3. How large would of gold be if it had a mass of 318.97 g?
The volume of the gold can be calculated using the formula: Volume = Mass / Density. Substituting the given values, Volume = 318.97 g / 19.32 g/cm^3 = 16.52 cm^3. So, the gold would have a volume of 16.52 cm^3.
If the mass density of gold is 193gramscubic centimeter and you were gave 15 kilograms of gold what is the volume?
To find the volume of gold, first convert the mass of gold to grams (1 kg = 1000 g), so 15 kg = 15000 g. Then, use the mass density formula: density = mass/volume, rearrange it to find volume: volume = mass/density. Plug in the values: volume = 15000 g / 19.3 g/cm^3 = 777.2 cubic centimeters.
Is the volume of gold 20g greater than the volume of lead 10g?
We need to calculate the volume of a metal from the density to be sure. Density of pure gold = 19.3  g·cm-3Density of pure lead = 11.34  g·cm-3The volume of 20 g of gold = mass/density = 20 [g] / 19.3  g·cm-3 = 1.036 cm3 The volume of 10 g of lead = mass/density = 10 [g] / 11.34  g·cm-3 = 0.882 cm3 Hence, the volume of 20 g of gold is slightly greater than that of 10 g of lead. =========================
The density of gold is 19.3 g cm3 The density of iron pyrite is 5.0 g cm3 If a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
The nugget of gold has a volume of 2.6 cm3, and the nugget of pyrite has a volume of 10 cm3.
Find the density of a piece of paper that has a mass of 15.5 g and a volume of 27.0 cm3?
The density of the piece of paper is calculated by dividing its mass (15.5 g) by its volume (27.0 cm3). Density = mass/volume = 15.5 g / 27.0 cm3 = 0.574 g/cm3.
What is the density of a piece that has a mass of 210 g and a volume of 20.0 cm cubed?
The density of the piece is 10.5 g/cm^3. This is calculated by dividing the mass (210 g) by the volume (20.0 cm^3). Density is a measure of how much mass is contained in a given volume.
How much volume will 180.0 g of gold occupy?
The volume of a substance can be calculated using its density. The density of gold is approximately 19.3 g/cm³. Using the formula: Volume = Mass / Density Volume = 180 g / 19.3 g/cm³ Volume ≈ 9.33 cm³ Therefore, 180.0 g of gold will occupy approximately 9.33 cm³.
A 34.5-g gold is dropped into a graduated cylinder containing water by how many milliliters does the measured volume increase?
The volume increase will be equal to the volume of the gold submerged in the water. The volume of the gold can be calculated by dividing its mass by its density (19.32 g/cm³ for gold). Submerging the gold in water will displace an equal volume of water, resulting in the measured volume increase.
