The radius of the tent, r = 5 m
Suppose the slant height = l m
Then the area of the cloth is pi*r*l = 165 m2
so l = 165/(5*pi) = 33/pi m = 10.504 m
If the vertical height of the tent is h m, then by Pythagoras,
h2 = l2 - r2 and therefore, h = 9.238 m
Then volume = 1/3*pi*r2*h = 241.85 m3
volume = 4/3 pi * (cubed radius)
A sphere with a radius of 9 units has a volume of 3,053.63 units3
volume sphere = 4/3 π radius³ → radius = ³√(¾ volume sphere ÷ π) = ³√(¾ × 972cm³ ÷ π) ≈ 6.1cm
cuboid volume = 49 * 344 * 318 = 5,360,208 cu. cm.>(sphere) volume = 4/3 * pi *r3>radius = cube root ( (3* volume) / (4 * pi) ) = 108.566 cm
Volume of a sphere is 4/3 pi times the cube of its radius.
Radius
The formula for the volume of a conical flask is V = (1/3)πr^2h, where V represents the volume, r is the radius of the base of the cone, and h is the height of the cone.
A quarter.
577.5 cubic metre
2 to 1
1 to 4
The volume would be 1436.7550...cm^3 and so on.
r = 3.989 cm
A conical cap is provided to a pscnometer to determine the volume of the test sample.
The volume of this cone is 15,400 cm3
I cannot imagine you could. both the radius and the height are considered in it's volume formula. this stands to reason as two cones of different radii can have the same volume, by the larger radius one having a smaller height and vice versa
If a big drop is formed by 1000 small droplets of water, the radius of the small drop can be calculated using the formula for the volume of a sphere. If the radius of the big drop is R, then the volume of the big drop is equal to 1000 times the volume of the small drop, given by the formula (4/3)pi(R^3) = 1000*(4/3)pi(r^3), where r is the radius of the small drop. By solving for r, we can find the radius of the small drop.