the equation for a line is y=mx+b where x and y are any point on a line, m is the slope, and b is the y-intercept. this equation is usually seen with numbers plugged into m and b, and y and x are left as is.
if you want to find the y-intercept of a equation and you have a point and a slope, than you wouldn't want to use this equation. you would want to use a similar one. so lets make it with some simple algebra.
y=mx+b
subtract mx from both sides
y-mx=mx-mx+b
simplify
y-mx=b
now you have a simple formula. take the slope of the line, multiply it by the y value, and subtract that from the x value, and you will get the y-intercept.
Find the slope of the line passing through (5, 5) and (-4, 5).
The slope would be 2,6.
The slope is -9.
The graph of [ y = 7 ] is a straight horizontal line, passing through the point [ y = 7 ]on the y-axis. The slope of a horizontal line is zero.
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The line passing through the point (0,0) with a slope of 7 would be y=7x.
you guts are lazy bums now answer your own questions....
It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]
It has not got a slope because it's a vertical straight line.
It is: y = 5x+6
If you mean passing through (1, 2) with a slope of -3 then it is y = -3x+5
There is no slope nor intercept because there is no equation, simply an expression.
To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
If the slope is undefined, it is a vertical line. Therefore the equation is x=2.
Points: (14, 5) and (20, 4) Slope: -1/6
If you mean a point of (-1, 4) and a slope of -3 then the equation is y = -3x+1