The z intercept occurs when x=y=0. Picture the z axis coming up from the floor. A good example is the corner of a room, The x-y plane is the floor and the z axis the the line coming up from the floor, perpendicular to it. This is the corner of the room. Now when would something intersect that line? It would happen when x=0 and y=0 If the equation is 5x-2y-4z-3=0 setting x and y to zero yields -4z-3=0 or 4z=-3 so z=-3/4
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If the x intercept is a and the y intercept is b, then the equation of the line is bx + ay = ab
2x-3y-4z=-24 has 3 potential intercepts. The x, y and z interceps. To find the x intercept we set y=z=0 This gives 2x=-24 or x=-12 To find the z intercept we set x=y=0 This gives -4z=-24 or z=6 Lastly to find the y intercept, x=z=0 so -3y=-24 and y=8 The x intercept is (-12,0,0), the y intercept is (0,8,0) and the z intercept is (0,0,6)
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Use the slope-intercept form of the line: y = mx + b Here, "m" is the slope, and "b" is the y-intercept, so just replace these variables with the corresponding slope and intercept - and you got your equation. And PLEASE don't ask lots of almost-identical questions, with different slopes and y-intercept. It is really easy to replace the slope and the intercept in this equation.
The equation y = mx + b is the equation for a line in slope intercept form, with m being the slope, and b being the y-axis intercept.