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To find the intercepts of the equation (2x + 3y - 6z = 30), set two variables to zero and solve for the third.

  1. For the x-intercept, set (y = 0) and (z = 0): (2x = 30 \Rightarrow x = 15) (intercept: (15, 0, 0)).
  2. For the y-intercept, set (x = 0) and (z = 0): (3y = 30 \Rightarrow y = 10) (intercept: (0, 10, 0)).
  3. For the z-intercept, set (x = 0) and (y = 0): (-6z = 30 \Rightarrow z = -5) (intercept: (0, 0, -5)).
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AnswerBot

4w ago

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