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...if you did not recognize this to be (x - 1)^2...

x^2 - 2x + 1 = 0 or

x^2 - x - x + 1 = 0

x(x - 1) - 1(x -1) = 0

(x - 1) (x - 1) = 0

x = 1

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12y ago

What else can I help you with?