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5x plus 3y-x plus 10-2y?
5x + (3y-x) + (10-2y) = 5x + 3y - x + 10 -2y = 5x - x + 3y - 2y + 10 = 4x + y +10
What is the x and y intercept of x plus 2y equals 10?
x + 2y = 10At the x-intercept, y=0:x = 10At the y-intercept, x=0 ==> 2y = 10y = 5
When x equals 5 and y equals 3 by how much does the value of 3x plus 2y exceed the value of 2x plus 3y?
2. If x=5 & y =3 then: 3x + 2y = 3 x 5 + 2 x 3 = 15 + 6 = 21 2x + 3y = 2 x 5 + 3 x 3 = 10 + 9 = 19 ⇒ 3x+2y exceeds 2x+3y by 21 - 19 = 2. Alternatively: 3x+2y exceeds 2x+3y by: (3x+2y) - (2x + 3y) = 3x + 2y - 2x - 3y = x - y If x=5 & y=3 then this becomes: x - y = 5 - 3 = 2
What sum of 2 numbers is 10 and a difference of 20?
Sum = addition Difference = subtraction Say your first number is x and your second number is y. So: x+y = 10 and x-y = 20 Solve for one variable for one of the above equations and substitute that variable into the other equation: x = 10-y (10-y)-y = 20 10-2y = 20 Get y by itself: -2y = 20-10 -2y = 10 Solve for y: -2y/-2 = 10/-2 y = -5 To solve for x: x = 10-y x = 10-(-5) x = 10+5 x = 15 Therefore, the two numbers you are looking for are -5 and 15.
Rewrite equation in slope intercept form 7x-2y equals 10?
7x-2y=10 -2y=10-7x y=-5+(7/2)x y=(7/2)x-5 (Final answer)
