Q: What is x to the third power subtracted by 5x to the second power plus 6x take away 8 factored?

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The next number is the sequence is 10. To find the second number, 1 was subtracted from the first number To find the third number, 2 was subtracted from the second number To find the fourth number, 3 was subtracted from the third number Therefore to find the fifth number, 4 must be subtracted from the fourth number. 14 - 4 = 10

a power is a power

Any number to the first power is that number - so 3 to the first = 3 Any number to the second power is that number multilpied by itself, so 3 to the second = 3 x 3 Any number to the third power is itself to the second power multiplied by itself, so 3 to the third = 3 x 3 x 3 and so on.. so three to the fourth = 3 x 3 x 3 x 3 As three is a prime number there are no other factors.

what is 7x to the third power + 6x to the second - 2

The GCF is a^2b

Related questions

The next number is the sequence is 10. To find the second number, 1 was subtracted from the first number To find the third number, 2 was subtracted from the second number To find the fourth number, 3 was subtracted from the third number Therefore to find the fifth number, 4 must be subtracted from the fourth number. 14 - 4 = 10

14x squared minus 7x to the 3rd power can be factored to 7x2(2-x).

a power is a power

simplified it would equal: 24x to the third power - x to the second power - x to the sixth power - 34

four to the second power

(-4)3 = (-4)*(-4)*(-4) = -4*4*4

Any number to the first power is that number - so 3 to the first = 3 Any number to the second power is that number multilpied by itself, so 3 to the second = 3 x 3 Any number to the third power is itself to the second power multiplied by itself, so 3 to the third = 3 x 3 x 3 and so on.. so three to the fourth = 3 x 3 x 3 x 3 As three is a prime number there are no other factors.

what is 7x to the third power + 6x to the second - 2

four to the fifteenth add the third to the second... and multiply it by the three answer: 1073741824

The GCF is a^2b

askdjfsakl

It's hard to write this on a typewriter keyboard. Do you mean xb + (1-x)b , or xb + 1 - xb , or maybe even x(b+1) - xb ? The first cannot be factored. The second equals 1, so it is already prime (cannot be factored). The third could be written as xb(x) - xb(1), so there is a common factor of xb, and the expression can be factored as xb(x-1). This is prime.