Q: What is y7 divided by y4?

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y4 times y3 = y7

The GCF is y4

x=y4 /2

4x-y4 what = 0

The simplest equation would be y4 = 0

(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)

(x2 + y2)(x + y)(x - y) = x4 - y4.

x=63xy-2/x39*x2y4/x69x2x6*y4

-2

y + y4 = y5 , possibly. Except that conventionally, the number (or coefficient) would be written first. y + y4 = y*(1 + y3) = y(1 + y)*(1 - y + y2)

y4

y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2