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What number can be divided by 2 3 4 5 6 7 8 9 and always gives remainder of 1 2 3 4 5 6 7 8 respectively?
Wiki User
∙ 12y ago
Actually, an infinite amount of numbers could follow this pattern. To figure it out, we can use algebra:
Let x be the number to divide by 23456789. So if there is a remainder than the answer of this division would some number, let's call it y + (12345678/23456789)
So we would have the equation:
x/23456789 = y + 12345678/23456789
Multiply both sides of the equation by 23456789 to get rid of the fractions & get:
x = y*23456789 + 12345678
Now just pick any number for y and solve for x & that'll be a number when divided by 23456789 will give a remainder of 12345678. So for simplicity pick y=1
x = 1*23456789 + 12345678
x = 35,802,467
Wiki User
∙ 12y ago
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