360
360
8
Well, honey, if you're looking for a number that, when divided by 9, equals 9, you're looking for 81. 81 divided by 9 gives you 9. So, there you have it, math wizard!
Half of 18 is 9. Eighteen divided by 2 gives you this number.
Yes. For example, if you multiply 9 x 8, you get a number that, when divided by 9, gives 8.
89
Remove the common factors. 6 = 3 x 2...as 3 is contained within the number 9 and 2 is contained within the number 8 then 6 is discarded. 4 is contained within the number 8 and is discarded 2 is also contained within the number 8 and is discarded. Take the product of the remaining numbers and subtract 1. (9 x 8 x 7 x 5 x 3) - 1 = 2520 -1 = 2519.......is the solution.
1.125
It is: 243/27 = 9
Use Number sense Write 2 numbers that cannot be divided evenly by 8 or 9.
72 divided by 9 equals 8. When you divide 72 by 9, you are essentially finding how many times 9 can fit into 72 without any remainder. Therefore, the whole number result of 72 divided by 9 is 8.
2519
80
69.
60 6*9+6=60 7*8+4=60
It is divisible by 8 because 202008/8 = 25251 But divided by 9 it will leave a remainder ----------------------- To test if a number is divisible by 8 add the ones digit to twice the tens digit to 4 times the hundreds digit; if this sum is divisible by 8 then so is the original number. By repeating the test on the sum until a single digit remains, only if this single digit is 8 is the original number divisible by 8, otherwise it gives the remainder when divided by 8 (except if it is 9, in which case the remainder is 1 - the excess of 9 over 8). For 202008: ones_digit + 2 × tens_digit + 4 × hundreds_digit = 8 + 2 × 0 + 4 × 0 = 8; so 208008 is divisible by 8. To test if a number is divisible by 9, add up the digits of the number; if this sum is divisible by 9, then so is the original number. By repeating the test of the sum until a single digit remains, only if this single digit is 9 is the original number divisible by 9, otherwise it gives the remainder when the original number is divided by 9. (This single digit is also called the "digital root" of the number.) For 202008: 2 + 0 + 2 + 0 + 0 + 8 = 12; 1 + 2 = 3; so 202008 is not divisible by 9; it has a remainder of 3 when divided by 9.